In order to know how many bits/second there are in 1 frame/second, you need to know how many bits are in that frame. In a typical asychronous serial protocol with 8 bits per frame, the bit rate would be 0.125 bits/second. If you are talking the IP network layer of TCP/IP, then the frame size is very dependent on the underlying message payload and headers.
The original question, by the way, is invalid. Its asks "how many bits does...", but it should have asked "how manys bits per second does...".
Baud is the number of symbols per second. So if you have a parallel interface where the 8 bits are sent together, I guess 300 bytes per second equates to about 300 baud. With a serial interface, where each of the 8 bits is sent one after the other, extra start/stop bits are usually inserted between the 8 data bits, I guess 300 bytes per second equates to about 3000 baud. Baud is the number of changes per second. Since computers use binary number to store information, the baud rate is directly equivalent to the number of bits sent per second. Specifically, in an ASCII character set 8 bits are used to represent a character, 300 bits per second would equate to 37.5 characters per second which in turn is 2250 characters per minute. (just under 2 kilobytes per minute assuming no error correction overheads).
600 bauds per second
On a modern 100Mb (million bits/second) broadband connection a megabyte transfers in 80 milliseconds (1.333E-3 minutes).
Baud rate is the number of samples per second. Data transfer rate is the number of bits per second. Since the analog phone line can have more than two values at any one sample, this translates to more bits per second than baud.There is a tendency to confuse baud rate with data rate. The two terms are not always the same.
The following are the major factors can affect network channel capacity: 1.Data rate-----Bits per second 2.Bandwidth---Cycles per second (Hertz) 3.Error rate
2 MB per second equals 16,777,215.9 bits per second.
kbps > Kilo Bits Per Second > 1024 bits per second mbps > Mega Bits Per Second > 1024 kilo bits per second
1 byte = 8 bits 1 byte per second = 8 bits per second 1 million bytes per year = 8 million bits per year
The system needs 8000 frames per second to maintain 24 simultaneous voice channels. Each frame is 193 bits in length (24 X 8 bits per channel + 1 control bit= 193 bits). 8000 frames per second is multiplied by 193 bits per frame which yields a rate of 1.544Mbps
Bit rate would be the number of bit processed per time frame, normally per second Old modems commonly worked as 4800 Baud or 9600 Baud which would be 4800 bits per second and 9600 bits per second respectively
The human brain on average takes in 11 million bits of information per second. However the brain is only aware of just 40 of those bits of information per second.
-- take the number of bits per second-- divide it by 8-- the result is the number of Bytes per second
100 megabits per second (Mbps) = 12800 kilobytes per second (KBps)
Assuming 12 bits for each pixel, rather than per color. The 105 bit per second sounds kind of slow, though. A 640 x 480 = 307,200 pixels. Multiply by 12 bits = 3,686,400 bits. So divide by 105 bits per second = 35,109 seconds, or about 9 hours 45 minutes.
Baud Width is an outdated Internet term. It refers to how many bits in a baud a modem can send per second. A baud is actually a pulse and carries a certain amount of bits per pulse. Nowadays its much simpler to refer to bits per second (BPS) since this is what Internet users wish to know; verses how many bits in a baud [pulse], and how many of these bauds are put out in a second.
Generally, but bit rate can be defined as any bit per unit of time so it could also refer to bits per minute, bits per hour or bits per day or bits per year etc...For the most part though bit rate is bits per second.
56k is fifty-six kilobits. That is, 56,000 bits per second.42 Mbps is forty-two million bits per second. That is, 42,000,000 bits per second- a four-order advantage.