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How many ml of 25percent dextrose and needed to prepare 500 ml of 40percent dextrose if you are to make 40percent dextrose from 25percent dextrose and 60percent dextrose?
My calulation says 286ml of 25% and 214ml of 60% 286 x .25= 71.50 214 x .60= 128.40 250 x .20= 50.00 250 x .60= 150.00
If an iv solution contains 5 percent wv of dextrose how many mg of dextrose is added by intravenous injection of 475 ml of this solution?
23.75 mg of Dextrose is added by intravenous injection of 475 ml of this solution .. wrong! 5% WV means 5 grams/100ml ; therefore 23.75 grams/475ml; since there's 1000mg…/gram the number of mg dextrose added by IV injection of 475ml = 23750mg !
Dextrose is a synonym of D-glucose (also known as grape sugar, corn sugar, and when it's present in blood, blood sugar). In 2013, Dextrose 5 percent in lactated Ringer…'s injection was recalled. This recall stemmed from allegations of the product having mold in it.
So you have to have a milligram for every millilitre. But you have 100ml. Therefore you have to multiply 1mg by 100, to get 100mg. Weigh out 100mg or 0.1g and dissolve it …to 100ml.
5% in pure water
How many 150 mg clindamycin capsules are needed to prepare 60 ml of a 1 percent clindamycin solution?
1% 1g in 100ml = 1000mg in 100ml in 60ml ? 100x = 1000 x 60 100x = 60000 x = 60000/100 = 600 150mg ? 600/150 = 4 answ…er = 4
How many mL of the 0.5 M NaCl stock solution is needed to prepare 500mL of 0.25 M NaCl solution How much water is needed to dilute the stock solution?
M1V1=M2V2 .5M x ?mL = .25M X 500mL Rearrange it and you get ?mL = (.25M x 500mL) / .5 Which equals 250mL needed of the .5M NaCl.
How many ml of a 20 percent solution should be added to 50 ml of a 40 percent solution to obtain a 25 percent solution?
150 ml Let x be the volume of 20% solution to add. The amount of "stuff" dissolved in the 20% solution plus the amount in the 40% will equal the amount of "stuff" dissolved i…n the 25% solution. (0.20)(X) + (0.40)(50 ml) = (0.25)(X+50ml) 0.2X + 20 = 0.25X + 12.5 20 - 12.5 = 0.25X - 0.20X 7.5 = 0.05X X = 7.5/0.05 = 150 ml
it depends on what you are trying to irrigate and what the solvent is.
125 ml 500(ml) * 0.05 = 25 25 / 0.20 = 125
0.06% W/V = 0.06g / 100ml = 60mg/100ml = 0.6mg/ml
add 25ml more of solution x * 20 = 100 * 25 x = 25
(X gal)(0.15) = (1 gal)(0.025) 0.15X = 0.025 X = 0.17 gallons (4 quarts/1 gal.)(1 liter/1.06 quarts)(1000 ml/1 liter) = 642 milliliters ====