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I believe you mean the formation of the compound calcium iodide. In the formation of calcium iodide, CaI2, the calcium atom transfers two valence electrons to two iodine atoms, with one electron going to each iodine atom. This causes the formation of a calcium ion, Ca2+, and two iodide ions, I-. The electrostatic attraction between the oppositely charged ions forms the ionic bonds that form the compound calcium iodide.

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10y ago
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16y ago

Due to a calcium atom having a valency of 2 and an iodine atom having a valency of 1, when the two elements react they form a molecule with the formula CaI2, or 1 calcium atom and 2 iodine atoms.

Therefore, calcium transfers 2 electrons, but 1 to each of the iodine atoms, so that all three newly created ions have stable outer shells.

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13y ago

Each calcium atom loses 2 electrons, but each Iodine atom accepts only 1 electron.

So, the resulting compound would be CaI2.

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14y ago

2

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14y ago

Two (2)

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13y ago

Two, Ca2+

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12y ago

2

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Q: How many valence electrons are transferred from the calciun atom to iodine in the formation of the compound calcium iodine?
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Related questions

How many valence electrons ars transferred from tbe calcium atom to iodine in the formation of the compound calcium iodide?

The formula for calcium iodide is CaI2. This means that the calcium atom has transferred one electron to each of two iodine atoms, for a total of two electrons transferred.


How many valence electrons are transferred from the calcium atom to iodine ine the formation of the compound calcium iodine?

The calcium atom will transfer its two valence electrons, one to each of two iodine atoms, to form the compound calcium iodide, CaI2.


How many valence electrons are transferred from the calcium Adson to iodine in the formation of the compound calcium Iodide?

Ca + I2 --> CaI2 Each calcium gives up 2 electrons to iodine when forming calcium iodide.


How many valence electrons are transferred from the calcium atom to iodine in the formation of the calcium iodide?

2


How many valence electrons are transferred from the calcium atom to iodine in the formatoin of the compound calcium iodide?

during the formation of calcium iodide,calcium donates two of its +ve ions each to a fluorine atom(2 in number) thereby making its octet and also fulfills the octet formation of each of fluorine atom..


How many valence electrons are transferred to make calcium iodide?

It takes only one valence electron to form the calcium iodide compound.


How many electrons are transferred in the ionic bond between Calcium and Oxygen?

Two electrons are transferred between calcium and oxygen to form calcium oxide.


How many electrons does one atom of calcium donate to one atom of oxygen during the formation of the compound CaO?

2


How many electrons of one atom of calcium donate to one atom of oxygen during the formation of the compound CaO?

2


How many valence elections are transferred from the calcium atom to iodine in the formation of the compound calcium iodine?

One calcium atom will transfer one of each of its two valence electrons to one each of two iodine atoms. In the process, the calcium atom becomes a calcium ion with a 2+ charge, and each iodine atom becomes an iodide ion with a 1- charge. The opposite charges between the iodide and calcium ions form an electrostatic attraction called an ionic bond, forming the ionic compound calcium iodide. Ca + I2 ---> I- + Ca2+ + I- ---> CaI2


If calcium sulfide forms when calcium loses 2 electrons what is formed?

ionic compound


How many valance electrons are transferred from the calcium atom to iodine in the formation of calcium iodide?

A calcium atom will transfer its two valence electrons to two separate iodine atoms in the formation of calcium iodide. The calcium atom becomes a Ca2+ ion, and each iodine atom becomes a 1- iodide ion. The electrostatic force of attraction between the oppositely charged ions forms ionic bonds between the ions.Ca + I2 --> Ca + I + I --> Ca2+ + I- + I- --> CaI2Overall reaction:Ca + I2 ---> CaI2