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If a battery has nine volts and three light bulbs with resistances of 10 20 and 30 then what is the voltage across lightbulb?
Wiki User
∙ 14y ago
If the three light bulbs are in parallel across the battery, then the full 9 volts appears
across each light bulb.
If the three light bulbs are in series across the battery, then the voltage divides among
them as follows:
Across the 10-ohm: 9 x (10/60) = 1.5 volts
Across the 20-ohm: 9 x (20/60) = 3 volts
Across the 30-ohm: 9 x (30/60) = 4.5 volts
Sum of the voltages across the 3 individual light bulbs = 1.5 + 3 + 4.5 = 9 volts.
Wiki User
∙ 14y ago
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What happens to a circuit if the resistances is increased?
The voltage drop across each resistance will go up, and the current through the circuit will go down.
What two factors determine the output energy of a battery?
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What is the total voltage drop across a set of resistors in series?
Simply add all of the component's resistances together and that will give you circuits total resistance. If you're dealing with a 'series-parallel', or 'parallel' circuit, the equations will change, but in a simple series circuit, the total resistance is just the total of all the component's resistance.
When a 12 V battery ie a battery of EMF 12 V is connected across a lamp with a resistance of 6.8 ohms the potential difference across the lamp is 10.2 V Find the current through the lamp?
The idea is to use Ohm's Law (V=IR). In this case, the relevant voltage is the 10.2 V across the lamp.
What is restriking voltage?
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What term remains the same across all the resistances in a parallel combination of resistances?
The voltage across the resistors will remain constant.
Modern electronic multimeter measures resistances by?
forcing a constant current and measuring the voltage across the unknown resistor.
In what part of the circuit do the electric charges releases most of their energy?
The component with the highest resistance in a series circuit will have, or "drop" the most voltage across it. All of the components in a series circuit will have the same amount of current flowing through them but not the same voltage drops if the resistances are different. More resistance more voltage across it, less resistance, less voltage across it.
Why is the voltage across a battery in a parallel circuit equal to the voltage across each bulb?
The voltage across a battery in a parallel circuit is equal to the voltage across each bulb because Kirchoff's Voltage Law (KVL) states that the signed sum of the voltages going around a series circuit adds up to zero. Each section of the parallel circuit, i.e. the battery and one bulb, constitutes a series circuit. By KVL, the voltage across the battery must be equal and opposite to the voltage across the bulb. Another way of thinking about this is to consider that the conductors joining the battery and bulbs effectively have zero ohms resistance. By Ohm's law, this means the voltage across the conductor is zero, which means the voltage across the bulb must be equal to the voltage across the battery and, of course, the same applies for all of the bulbs.
A light bulb is wired in series with a 144 resistor and they are connected across a 120 V source The power delivered to the light bulb is 22.2 watts What are the two possible resistances of the light?
There is only one possible answer.Voltage = current * resistancealso, Power = Voltage * Voltage / resistanceIf you follow the algebra, you should get a resulting resistance of the lightbulb to be 548.6 ohms.
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In a parallel circuit, Voltage is constant through out the circuit. Thus, the voltage across each lamp is 6-volts.
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The voltage drop across each resistor is determined by the amounts of resistance in the 3 resistors and all the rest of the resistances in the electrical circuit.
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The voltage drop across each resistance will go up, and the current through the circuit will go down.
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All the volt drops across each component in the series circuit will add up to the emf of the battery or power supply. Note the voltage supplying the circuit and divide it by the sum of all the resistances in the circuit. This gives you the current which is the same through all components. Take a component's resistance and multiply by the current and you have the voltage drop across it.
A battery of emf 2V is connected to an external resistance which is equal to its internal resistance and then find potential difference across the external resistance?
As the source impedance is equal to load impedance, it is assumed that both the resistances are in series. This distributes the whole voltage equally between both the impedance. Hence the PD across external resistance will be 1V.
When a voltmeter is place across a forward biased diode it will read a voltage?
(A) The bias battery voltage (B) 0V (C) the diode barrier potentiaol (D) The total circuit voltage
