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Voltage = current * resistance
also, Power = Voltage * Voltage / resistance

If you follow the algebra, you should get a resulting resistance of the lightbulb to be 548.6 ohms.

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Q: A light bulb is wired in series with a 144 resistor and they are connected across a 120 V source The power delivered to the light bulb is 22.2 watts What are the two possible resistances of the light?
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