Color blindness is an X-linked trait. That means it is carried in the X chromosome, which differentiates whether a baby will be a girl or a boy. Women have two X chromosomes (XX), and men have an XY combination. If a woman is a carrier for color blindness, only one of her chromosomes will be affected (we'll call it a little "x"), and for that reason she will not be colorblind. Men, on the other hand, only have one X chromosome, so any time they carry the colorblindness gene, they will be colorblind. A woman will carry the colorblindness gene if:
a. Her father is colorblind
b. Her offpsring are colorblind
She may carry the colorblindness gene if:
a. Male family members (brothers, uncles, etc.) are colorblind
A child inherits one chromosome from each parent. He/She will get an X chromosome from his/her mother, and an X from her father (if a girl) or a Y from his father (if a boy)
So, If a woman has normal vision (assuming she does not have a family history of colorblindness), XX, and a man is colorblind, xY, they have several different chances for different offspring:
Xx (a normal girl who carries the colorblindness gene)
XY (a normal boy)
Xx (a normal girl who carries the colorblindness gene)
XY (a normal boy)
The short answer is that ALL CHILDREN WILL HAVE NORMAL VISION. However, all daughters will be CARRIERS, meaning they can pass colorblindness on to their children.
possibly; if the kid was a male; then it will have more chances of being color blind, because the father will transport his genes to the male kid. If the mother is not color blind and the child was a girl she would most likely not be color blind; because the female parent will transport her genes to the female child.
Because of genes maybe.
yes it will because the colorblind gene is located in the x chromosome. if the mother is colorblind, she has the gene in both of her x- chromosomes. She will pass down the gene and because the father passes down a y chromosome, it doesn't matter if the father is colorblind or not.
Colour blind females are quite rare, but since females carry the gene to the next generation it is highly likely.
50%
100% of all male offspring will be colorblind. 0% of all femal offspring will be colorblind.
There is no chance for a colorblind daughter because the x-chromosome that comes from the male is normal and then it does not matter which x-chromosome comes from the female because colorblindness is a recessive gene, therefore there is no chance.
Make a punnet square with the mother above, her genotype would be: X^B X^b, and the father to the left whose genotype is X^b Y.The probability of having a colorblind CHILD is 50%. The probability of them having a SON is 50%. Since we are asked what the probability of their SON being colorblind, it is 50% as well. The reason is because the chance of having a colorblind son, among sons only, (according to the punnet square) is 50%.
50%Answer100%
It all will depend on what kind of (recessive or dominant) alleles are responsible for the colorblind characteristic and what kind of alleles do the parental genes have.
In short, hemophilia has nothing to do with colorblindness, but YES, they could have a colorblind child if she is a carrier for the colorblindness gene. Color blindness is an X-linked trait. That means it is carried in the X chromosome, which differentiates whether a baby will be a girl or a boy. Women have two X chromosomes (XX), and men have an XY combination. If a woman is a carrier for color blindness, only one of her chromosomes will be affected (we'll call it a little "x"), and for that reason she will not be colorblind. Men, on the other hand, only have one X chromosome, so any time they carry the colorblindness gene, they will be colorblind. A woman will carry the colorblindness gene if: a. Her father is colorblind b. Any of her offpsring are colorblind She may carry the colorblindness gene if: a. Male family members (brothers, uncles, etc.) are colorblind A child inherits one chromosome from each parent. He/She will get an X chromosome from his/her mother, and an X from her father (if a girl) or a Y from his father (if a boy). So, If a woman has normal vision (assuming she does not have a family history of colorblindness), XX, and a man is colorblind, xY, they have several different chances for different offspring: Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) The short answer is that ALL CHILDREN WILL HAVE NORMAL VISION. However, all daughters will be CARRIERS, meaning they can pass colorblindness on to their children.
The daughter's father would have to have been colour blind, and the mother would need the inheritive gene from her father (the mother doesn't nessecarily need to show it, just have a colourblind father) in order for a female to end up actually colourblind. However, it's extremely rare.
Under normal circumstances the chances of that would be about zero, unless of course, there is an arsonists in the mix.
Assuming that the man who has normal vision is homozygous for normal vision, the couple's daughter will either be homozygous for normal vision or heterozygous (normal vision but carrier for color blindness) for normal vision. In light of this, the couple's daughter will not be color blind.
Colorblindness is a sex-linked trait carried on the X chromosome. Males have an X and a Y chromosome (XY) and females have two X chromosomes (XX). Normal vision is dominant over colorblindness. This means that the man must have an allele for normal vision on his only X chromosome. This also means that the woman must have two colorblind alleles on both of her X chromosomes. If we use a capital 'B' to represent normal vision and a lowercase 'b' to represent colorblindness, the genotype of the male would be XBY, and the genotype of the female would be XbXb. Now that we know the genotypes, setting up the Punnett square should be easy. Here is a direct image link to the Punnett square: http://i.imgur.com/gDfUv.png This Punnett square tells us that there is a 50% chance of having a female that has normal vision and a 50% chance of having a colorblind male.
It depends on a number of different factors. If colorblind is common in either family but the mother/father were lucky enough not to get it, then its a recessive gene. but if its not common in either family then its a very low chance the child will be color blind. Although, if there are numerous people on both sides of the family the probability is very high. It all depends on a lot of different factors. How dominant is the gene? How many relatives are colorblind? If there are any, and they have children, are they colorblind? The easiest way to figure out if the child will be colorblind is to have the kid and test it for colorblind-ness.