Potassium permanganate = KMnO4
Molar mass of KMnO4
K = 1 * 39.10 g = 39.10 g
Mn = 1 * 54.94 g = 54.94 g
O = 4 * 16.00 g = 64.00 g
Total = 158.04 g/mol
17.34 mol KMnO4 * (158.04 g/1 mol KMnO4) = 2740.41 g KMnO4
Convert the grams to kilograms. 1 kg = 1000 g
2740.41 g * (1 kg/1000 g) = 2.74041 kg
Therefore, 17.34 moles of potassium permanganate is equal to about 2.74 kilograms.
1,5 moles of potassium carbonate have 276,41 g.
Since molecules of potassium contain only single potassium atoms, molecules of iodine contain two atoms, and moles of potassium iodide contain one atom of each element, 2.5 moles of iodine are needed to react completely with 5 moles of potassium.
In one mole of potassium dichromate, there seven moles of oxygen. This means in two moles of K2Cr2O7, there are 14 moles of O, or 7 Moles of O2, which equals 224 grams.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Algebraically manipulate, moles of solute = Liters of solution * Molarity Moles KMnO4 = (0.075 Liters)(0.0950 M) = 7.13 X 10 -3 moles KMnO4 ------------------------------------
The amount of potassium phosphate in the solution is 1.27 M * 0.343 L = 0.43561 moles.The chemical formula of potassium phosphate is K3PO4, so there is three times as many moles of potassium as there are moles of potassium phoshate in the molecule:0.43561 * 3 = 1.30683Answer: 1.31 moles
This mass is 347,67 for KMnO4.
The solubility of potassium permanganate in water at 2o 0C is 64 g/l (or 32 g/0,5 L).The molar mass of KMnO4 is 158,034 g and 0,35 moles KMnO4 is equal to 55,312 g.So it is not possible to dissolve o,35 moles KMnO4 in 0,5 L.
1,5 moles of potassium carbonate have 276,41 g.
The compound potassium permanganate has chemical formula KMnO4 Molecular mass of KMnO4 = 39.1 + 54.9 + 4(16.0) = 158.0 Mass of KMnO4 = amount of KMnO4 x Molecular mass of KMnO4 = 2.55 x 158.0 = 403g
Molality is the number of moles of a solute divided by the weight of the solvent in kilograms.
In order to find the actual number of Oxygen atoms in that substance, you must first find the molar mass of that substance by adding the atomic masses of all the atoms which make up that compound. Then, divide the mass of the substance you have by that molar mass. After that, multiply that amount by how many Oxygen atoms are in a molecule of the substance to find how many moles of oxygen you have. Then finally, multiply the number of moles of Oxygen by Avogadro's number (6.022*10^23).
there are two moles produced in potassium nitrate.
12 g of potassium is equivalent to 0,307 moles.
Since molecules of potassium contain only single potassium atoms, molecules of iodine contain two atoms, and moles of potassium iodide contain one atom of each element, 2.5 moles of iodine are needed to react completely with 5 moles of potassium.
34,7 moles of potassium 1 356,7 g.
You did not describe the amount of potassium bicarbonate amount in grams in your question. But if you are about 1 gram of potassium bicarbonate it will be 0.0099 moles in one gram of potassium bicarbonate. 0.0199 moles in 2 grams of potassium bicarbonate.
Four moles of potassium chlorate are needed.