Copper sulfate dissolves in water, it does not react.
CuSO4 is copper (II) sulfate. The balanced equation for CuSO4 with water is CuSO4 + H2O reacts to become Cu+2 + HSO4-2 + OH-.
CuO + H2SO4 --> CuSO4 + H2O
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
CuSO4 + KCN --->Cu(CN)2 + K2SO4
CuO + H2SO4 -> CuSO4 + H2O copper sulfate and water produced
CuSO4 is copper (II) sulfate. The balanced equation for CuSO4 with water is CuSO4 + H2O reacts to become Cu+2 + HSO4-2 + OH-.
CuO + H2SO4 --> CuSO4 + H2O
Let's see! CuO + H2SO4 --> CuSO4 + H2O ======================== This reaction is what I think would theoretically happen here; a salt, copper sulfate, and water produced.
Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
penta = 5 copper(II) sulphate pentahydrate = CuSO4*5 H2O CuSO4*5 H2O + heat --> CuSO4 + 5 H2O
CuSO4 + KCN --->Cu(CN)2 + K2SO4
Sulphurous acid is formed H2O + SO2 ----> H2SO3
CuO + H2SO4 -> CuSO4 + H2O copper sulfate and water produced
H2O CuSo4 Ca2So4
The net ionic equation when ammonium perchlorate reacts with water is NH4++ H2O --> NH3+ H3O+