Acetic acid + Sodium Bicarbonate ----> Sodium Acetate + Water + Carbon Dioxide
CH3COOH + NaHCO3 ----> NaCH3COO + H2O + CO2
CH3COOHaq + HCO3-aq + [Na+]trib. --> CH3COO-aq + H2Ol + CO2,g + [Na+]trib.
CH3COO-NA+ + H20 + CO2
it blows up
CH3COOH + NaHCO3 = CH3COO-Na+ + H2O + CO2
It doesn't need balancing - it's already balanced. NaHCO3 + NaOH → Na2CO3 + H2O
Yes. Sodium bicarbonate is a base.
the balanced chemical equation when sodium bicarbonate breaks down into sodium oxide carbon dioxide water is represented as follows.2 NaHCO3(s) CO2(g) + H2O(g) + Na2CO3(s).
K2HPO4 + NaHCO3 --> K2NaPO4 + H2O + CO2 is the balanced equation for the reaction of dipotassium hydrogen phosphate and sodium bicarbonate. (All numbers should be subscripts). Dipotassium phosphate does not exist. Tripotassium phosphate, K3PO4 does, but it's not acidic and therefore does not react with sodium hydrogen carbonate (sodium bicarbonate).
CH3COOH + NaHCO3 ---> CH3COONa + H2O + CO2
Acetic acid
sodium bicarbonate reacts with acetic acid to form sodium acetate and carbonic acid. carbonic acid will further dissociate to form water and carbon dioxide
NaHCO3 + HCl -> Na+ + H20 + CO2 + Cl-
By the reaction of Acetic Acid with sodium bicarbonate, Carbon dioxide will evolve, this gas has no smell, thefore there will be no smell given off in the reaction of acetic acid and sodium bicarbonate.
I assume you mean you want the molecular formula for sodium bicarbonate - if you wanted a balanced equation, you would need another substance to react with But sodium bicarbonate = NaHCO3 While the above answer is help full I am going to assume that the question was what is the balanced equation for the decomposition of sodium bicarbonate. 2NaHCO3--> Na2CO3+CO2+H2O in further detail the reaction for this formula is not decomposition; it is, in fact, combustion because of the carbon dioxide and water in the products of the equation.
Sodium bicarbonate is a weak base.