The electronic configuration of chlorine is 1s2, 2s2 2p6, 3s2 3p5.
Chlorine has 17 electrons. The number of electrons in an electrically neutral atom is equal to its atomic number (the number of protons in the nucleus of the atom). The electronic configuration of chlorine is [Ne] 3s2 3p5.
The chemical element with the atomic number 41 is niobium; the electron configuration is:[Kr]4d4.5s1.
Iodine is a non metal element. Atomic number of it is 53.
The element is Argon. Its configuration is 2 8 8.
The electron configuration of chlorine is 1s2 2s2 2p6 3s2 3p5. This means that chlorine has 17 electrons distributed in its electron shells, with two electrons in the first shell, eight in the second, and seven in the third.
Atomic number for sodium is 11. 2-8-1 is the electronic configuration of sodium.
The atomic number of Sodium is 11 (2,8,1), so there is one electron in the outer-most shell. As soon as sodium looses this outer-most one electron, it acquires the stable most structure with a 2,8. That';s why sodium ion is stabler than sodium metal. The electronic configuration of a sodium ion is 2,8. Same thing happens with Chlorine. The electronic configuration of chlorine is 2,8,7. Chlorine needs just one electron to stabilize itself with a configuration of 2,8,8. When the chlorine atom gains one electron, it forms the chlorine ion which has the configuration 2,8,8 which is stable.
By rings, I assume you mean sub-atomic shells. Chlorine has an atomic number of 17. This means that it will have 17 electrons. The electron configuration will be as such: 2, 8, 7. Hence, chlorine will have 3 sub-atomic shells to fulfil its electronic configuration.
The atomic number of Chlorine is 17.
The number of electrons on the external level is generally equivalent to valency.
The electronic configuration of bromine is 1s2, 2s2 2p6, 3s2 3p6 3d10, 4s2 4p5.
The electron configuration for chlorine is 1s2 2s2 2p6 3s2 3p5.