The 8086/8088 microprocessor has a 20 bit address bus, so the number of memory locations it can address is 220 or 1,048,576.
The 8086/8088 does not have 1 MB memory, rather, it can address 1MB memory. The processor has a 20 bit address bus. With that, it can select among 220 distinct addresses, or 1,048,576 addresses. That is 1 MB of memory.
since 8086 has 20-bit address line
therefore 2^20=1048576 bytes=1048 KB=1MB
Hence Addressing up to 1MB memory
vivek Lunkar
The 8086/8088 microprocessor has a 20 bit address bus, so the number of memory locations it can address is 220 or 1,048,576.
nonsence website
20
Microprocessor has 16 address lines and microcontroller has 20 address lines
The number of address lines needed to access N-KB is given by log2N Then the number of address lines needed to access 256KB of main memory will be log2256000=18 address lines.
the 8085 microprocessor is a 8-bit microprocessor and these are bidirectional but the address lines are unidirectional.these address lines are used to address the location of the instruction in memory .these data lines are used to transfer data between processor and peripheral devices. when the address of the instruction will be recognized by the address lines the data will be send to the processor therefore the 16 address lines are not act as a data lines in 8085
A microprocessor with 12 address lines is capable of addressing 4096 locations in memory. The Intel 4004 and the DEC PDP-8 are examples of processors with 12 address lines.
2kb=2*1024=2048 2^11=2048 therefore 11 address lines are required
segment is for converting physical address to logical address , here on taking 8086 microprocessor as example, we have 20 address lines but it is capable of taking only 16 address lines.... so to convert that 20 into 16 segment is used....
In the 2k*16 , the 11 address lines are required and the 16 input-output lines are required..
1)address lines to refer to the address of a block 2)data lines for data transfer 3)IC chips 4 processing data
You can address 214 or 16384 different locations with 14 address lines.
1)address lines to refer to the address of a block 2)data lines for data transfer 3)IC chips 4 processing data
There are 20 address lines and 16 data lines in the 8086 microprocessor. The low order 16 address lines are multiplexed with the data lines. Some of the high order address lines are multiplexed with status lines.
20 address lines are required