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HCl + KOH ==> KCl + H2O
KOH + HCl → H2O + KCl Potassium hydroxide will react with hydrochlric acid to produce an insoluble precipitate, potassium chloride, as well as water. This is a strongly exothermic reaction.
HCl + NaOH = NaCl + H2O
HCL (hydrochloric acid) and KOH (Potassium hydroxide)HCL + KOH = KCL + H2Oso you need hydrochloric acid and potassium hydroxide.
The balanced equation is: KHCO3 + HCl -> KCl + CO2 + H2O The products of the reaction are potassium chloride, carbon dioxide and water.
HCl, hydrochloric acid, is the primary standard used to titrate against potassium hydroxide.
Acid + Alkali -> Salt + Water For this case, Hydrochloric acid + Potassium hydroxide -> Potassium chloride + water HCl + KOH -> KCl + H2O
Potassium hydroxide is a base.
KOH + HCl --> KCl + H20
KOH + HCl = KCl + H2O
first things first, i don't think KH(SO4)k(OH) with K(SO4)H2O is a real balancing chemical equation.
NaOH(hydroxide) + HCl(acid) ---------> NaCl(salt) + H2O(water)