255.255.252.0
22 Network Bits = 2 full octets (255.255) + 6 bits (252)
Its a Class B IP address so the subnet mask is 255.255.0.0 by default. If Subnetting is done then the SNM changes.
yes
You have given a subnet mask; it has nothing to do with hosts. You would need to supply the network number.
255.255.252.0 is true
If you need to divide it up into the maximum number of subnets containing at least 500 hosts each, you should use a /23 subnet mask. This will provide you with 128 networks of 510 hosts each. If you used a /24 mask, you would be limited to 254 hosts. Similarly, a /22 mask would be wasteful, allowing you 1022 hosts.
255.255.254.0
195.85.8.0 is a class C network. The subnet mask would be 255.255.255.0 and the network address is 195.85.8.0
255.255.252.0
255.255.252.0
If this is a default subnet mask, then it would be a class C subnet mask. If you are subnetting a network and this is not the default subnet mask, then it could be either a class A or class B.
253. Valid addresses would be from 10.20.50.1 to 10.20.50.254 10.20.50.0 is the network address. 10.20.50.255 is the network broadcast address. Any network with a subnet mask of 255.255.255.0 will support 253 hosts.
The network address of an IPv4 address of 192.168.7.5 with a subnet mask of 255.255.255.0 would be 192.168.7.0. Remember that the subnet mask determines the network portion of the IP Address.
151.242.16.49 would be class B in a classful environment with a network mask of 16 bits. An additional 7 bit subnet mask puts the total mask at 23 (i.e.: 255.255.254). Subnet ID would be: 151.242.16.0 Host address range: 151.242.16.1 through 151.242.17.254 Subnet Broadcast address would be: 151.242.17.255