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KMnO4 and H2SO4 are oxidising agents. Oxidising agents are hungry for electrons...
When ethanol is added to alkaline KMno4 solution, the ethanol gets oxidised to ethanoic acid due to nascent oxygen. KMno4 is an oxidising agent. thus when we first add alkaline Kmno4 to ethanol, the pink colour of the Kmno4 vanishes, as it is being used up for the oxidation process. however. when all of the ethanol has been oxidised into ethanoic acid, and we keep adding Kmno4, the colour returns, as there is no more ethanol left to oxidise.
The balanced chemical equation would be K4FeC6N6 + KMnO4 + H2SO4 = KHSO4 + Fe2SO43 + MnSO4 + HNO3 + CO2 + H2O.
KMno4 is reduced to Mn^2+ Salt and the pink colour is discharged by the nascent hydrogen produced when zinc reacts with h2so4
Kbr
KMnO4 is pink in a solution without oxidizing reagents. Adding ethanol should change it to a brown solution. If adding ethanol can not change the solution to brown, then its environment is already acidic and will not reduce.
FeCl2 + 2KMnO4 --> Fe(MnO4)2 + 2KCl
odour,melting/boling point,solubility in water,sooty or non- sooty flame on combusion,sodium fusion test,colour on adding KMnO4..
Because KMnO4 is an internal indicator.. No need to have any indicator.. it has distinctly different colour when it is reduced
The permanganate ion, MnO4- purple in colour. The sulfuric acid is added to create acidic conditions. In acidic conditions, the MnO4- gets reduced to Mn2+ which is colourless. Therefore, judging by the colour change, we can figure out how much of the potassium permanganate has been used.
The answer is: 4 KMnO4=2 K2O+4 MnO+5 O2
by adding 158.0g in 1 liter water.