by adding 158.0g in 1 liter water.
2 TABLETS
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
The molar mass of KMnO4 is 158,3415 g.The molarity of this solution is 0,1 M.
To prepare 2L of a 5M solution, you should put in 4.6575grams of KMnO4. It is important to make sure that you add them in that order. K should be added first, then Mn.
24 g
KMnO4 will react with compounds having unsaturation (double bond or triple bond). Since alkenes have double bond, it will react with KMnO4 and decolourize dilute KMnO4 solution.
6.023 X 1023 particles make up a 1M solution.
There is no such solution.You probably mean KMnO4 which is Potassium Permanganate solution.
0.056g
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Algebraically manipulate, moles of solute = Liters of solution * Molarity Moles KMnO4 = (0.075 Liters)(0.0950 M) = 7.13 X 10 -3 moles KMnO4 ------------------------------------
a dilute aqueous solution of KMnO4 may be used.
4 x. Take 25ml of 0.2 M solution and dilute to 100ml.