answersLogoWhite

0


Best Answer

To prepare 2L of a 5M solution, you should put in 4.6575grams of KMnO4. It is important to make sure that you add them in that order. K should be added first, then Mn.

User Avatar

Wiki User

10y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many grams of KMnO4 should be used to prepare 2L of a 5M solution?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How many moles of KMnO4 are present in 75.0 mL of a 0.0950 M solution?

Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Algebraically manipulate, moles of solute = Liters of solution * Molarity Moles KMnO4 = (0.075 Liters)(0.0950 M) = 7.13 X 10 -3 moles KMnO4 ------------------------------------


How do you prepare 30 percent sucrose solution?

See the two Related Questions to the left for the answer.The first is how to prepare a solution starting with a solid substance (and dissolving it). The second question is how to prepare a solution by diluting another solution.


How many grams of sulfosalicylic acid are required to prepare 1 liter of 3 solution?

30 grams


How many grams KMnO4 take in 0.1N KMnO4 solution?

(158 g = 1 mole) --- molar mass of potassium permanganate. You also need to specify the volume to be made. For 1 liter just add 15.8 g in a volumetric flask to make 1000 ml (1 liter) of solution.


How many grams of active ingredient will you need to prepare 2.5 gallons of a 45.6 percent solution?

4314.9 grams


How many grams of I2 should be added to 750 g o C Cl4 to prepare a 020 m solution?

If this is .020m solution, you need 3.81g If this is .20m solution, you need 38.1g If this is 20m solution, you need 3810g


What is the molality of a solution of chlorine and water is 0.0362 m how much chlorine in grams was used to prepare this solution?

8.9g


- How many grams of water should be added to prepare a 2% solution by mass with 16.5g of MgCl….A) 402.5B) 808.5C) 155D) 400E) 82.5?

E


How many grams of potassium permanganate KMnO4 are in 2.55 moles?

The compound potassium permanganate has chemical formula KMnO4 Molecular mass of KMnO4 = 39.1 + 54.9 + 4(16.0) = 158.0 Mass of KMnO4 = amount of KMnO4 x Molecular mass of KMnO4 = 2.55 x 158.0 = 403g


How many grams of a drug must be used to prepare 2 liters of a 1 percent solution?

1% solution = 1 gram per 100 mL, 10 grams per liter 20 grams


How to prepare 100 ppm solution of KMnO4?

I will assume that you will start from the crystals of permanganate: Calculations: M.M. potassium permanganate: 158.04 g/mol mol KMnO4 in 10mL sol'n: 1.5 mol/L x 10 mL x (1 L / 1000 mL) = 0.015 mol grams potassium permanganate: 0.015 mol x 158.04 g/mol = 2.3706 g / 10 mL sol'n Preparation: 1. Weigh out analytically 2.3706g KMnO4 into a 10 mL volumetric flask. 2. Dilute to the mark with dH2O.


What is the mass of sodium hudroxide needed to prepare 100 mL of a 0.10 M solution?

1.17 grams :)