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*first you set the equation: -(10mL of HCl)(1 mol of HCl)/(22.4 mL of HCl)= .446 mol of HCl *you divide by the volume of HCl which is 22.4 at STP. *Then you will divide that .446 mol of HCl with the mol of Zn, which is 1: -(.446 mol of HCl)( I mol of Zn)/(1 mol of HCl)= .446 mol Zn

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Q: .25 g of zinc reacted with 10 mL of HCl what is the moles of zinc reacted?
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What is the minimum molarity of HCl when titrated with 18.6ml of NaOH?

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