The molarity is 0,41 mol/L.
Need an equation as this is not familiar to me. Where is the carbon coming from? Moles? Molarity. All info I do not have.
1.54 moles H2O (18.016 grams/1 mol H2O ) =27.7 grams
Molarity = moles of solute/Liters of solution Molarity = 25 moles sucrose/50 liters H2O = 0.5 M sucrose
1.002 M
I suppose that this situation is not possible.
Molarity= Number of moles of solute/Liters of solution 50 grams KOH 700 ML to .7 Liters of h2o Molar Mass of KOH= 56 50 divided by 56 = .89 moles Molarity= .89 mol/.7 L = 1.27 MOLARITY
Need an equation as this is not familiar to me. Where is the carbon coming from? Moles? Molarity. All info I do not have.
Molarity = moles of solute/Liters of solutionThat 3 kg of water would present a problem, but water = 1 gram/ml in density, so....3 kg = 3000 grams1g/ml H2O = 3000 grams H2O/X ml= 3000 ml = 3 Litersso,Molarity = 6 moles Na/3 Liters= 2 M NaOH-----------------
1.54 moles H2O (18.016 grams/1 mol H2O ) =27.7 grams
Molarity = moles of solute/Liters of solution Molarity = 25 moles sucrose/50 liters H2O = 0.5 M sucrose
1.002 M
200 grams H2O (1 mole H2O/18.016 grams)(6.022 X 1023/1 mole H2O) = 6.69 X 1024 molecules of water ======================
Let me help you a little: water is H2O
Approx 18 grams.
45 grams H20 x (1 mole H20/18 grams H2O) x (6.02E23 molecules H20/1 mole H2O) the grams H2O and moles H2O cancel out. When you punch it into your calculator, the answer comes out to: =1.505E24 molecules H2O
1 mole is equal to 18 grams of H2O, so 60 grams is 3.33 moles.
301.8g H2O