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to find the memory from address lines. you just have to make address liness power of 2, as shown below for 12 address lines 212 bits. 212 = 22 * 210 = 4 Kb
that means we can address 4 Kb from 12 address lines.........

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14y ago
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12y ago

2^12 = 4096

4096= 1024*4=(2^10)*4= 4 kbytes

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14y ago

18 address lines is 218 or 262,144 different addresses.

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13y ago

it maps the memory of 4096 byte i.e 2^12=4096 byte

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Q: 18 address lines is how much memory?
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