For this you need the atomic (molecular) mass of NaCl. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. NaCl=58 grams
25.0 grams NaCl / (58 grams) = .431* moles NaCl
*approximation
The answer is 146,099 423 2 g.
This value is 0,043 moles.
The answer is 6,022 141 29(27).1023.
there is .42 moles
Sr is 87.6g/mol, and 25/87.6 = 0.285 moles.
.071 moles
Use stoichiometry. 3.5g-> moles 22.99+16+1.0079=39.99 Now 3.5/39.99 = .088 moles of NaOH Now you can use avagadros number 6.022x10^23 .088 moles -> formula units .088/6.022x10^23 You should end up with 1.46x10-25 formula units. Yeah, I know, Chem sucks huh?
The answer is 29,22 g NaCl.
25 moles of sulfur dioxidecontain 800,825 g oxygen.
It is 25 moles of Sodium Hydroxide (;
The formula mass of sodium hydroxide, NaOH is 23.0+16.0+1.0=40.0 Amount of NaOH in 25.0g sample = 0.625mol
800 g oxygen are needed.
I think you meant " How many moles of acetic acid in 25 grams of acetic acid? " We will use the chemist formula for acetic acid, 25 grams C2H4O2 (1 mole C2H4O2/60.052 grams) = 0.42 mole acetic acid =================
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
5 moles of lead is equal to 1 036 g.