For this you need the atomic (molecular) mass of NaCl. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. NaCl=58 grams
25.0 grams NaCl / (58 grams) = .431* moles NaCl
*approximation
To calculate the number of moles in 25 grams of NaCl, divide the given mass by the molar mass of NaCl. The molar mass of NaCl is approximately 58.44 g/mol. Therefore, 25 grams of NaCl is equivalent to approximately 0.43 moles.
Use stoichiometry. 3.5g-> moles 22.99+16+1.0079=39.99 Now 3.5/39.99 = .088 moles of NaOH Now you can use avagadros number 6.022x10^23 .088 moles -> formula units .088/6.022x10^23 You should end up with 1.46x10-25 formula units. Yeah, I know, Chem sucks huh?
The molar mass of sodium hydroxide (NaOH) is approximately 40 grams/mol. To find the mass of 25 moles of NaOH, you would multiply the number of moles by the molar mass: 25 mol * 40 g/mol = 1000 grams. So, the mass of 25 moles of sodium hydroxide is 1000 grams.
Sr is 87.6g/mol, and 25/87.6 = 0.285 moles.
To find the molarity, first calculate the moles of Sodium Chloride using its molar mass. Assuming 58.44 g/mol for NaCl, 2.3 grams is 0.039 moles. Then, divide this by the volume of solution in liters (25 mL = 0.025 L) to get a molarity of 1.56 M.
To calculate the number of moles in 25 grams of UF6, first determine the molar mass of UF6 (uranium hexafluoride) by adding the atomic mass of uranium (238.03 g/mol) to six times the atomic mass of fluorine (19.00 g/mol). This gives a molar mass of 238.03 + (6 * 19.00) = 352.03 g/mol. Next, divide the given mass of 25 grams by the molar mass to find the number of moles: 25 g / 352.03 g/mol ≈ 0.071 moles. Therefore, there are approximately 0.071 moles in 25 grams of UF6.
To find the number of moles of NaOH in 25.0 g, you first need to determine the molar mass of NaOH (40.00 g/mol). Then, divide the given mass by the molar mass to get the number of moles: 25.0 g / 40.00 g/mol = 0.625 mol of NaOH.
I think you meant " How many moles of acetic acid in 25 grams of acetic acid? " We will use the chemist formula for acetic acid, 25 grams C2H4O2 (1 mole C2H4O2/60.052 grams) = 0.42 mole acetic acid =================
The answer is 29,22 g NaCl.
800 g oxygen are needed.
1 mole NaCl = 58.443g NaCl = 6.022 x 1023 formula units NaCl 3 x 1025 formula units NaCl x 1mol NaCl/6.022 x 1023 formula units NaCl x 58.443g NaCl/mol NaCl = 2911g NaCl = 3000g NaCl (rounded to 1 significant figure)
25 moles of sulfur dioxide contain 600 grams of oxygen. Each mole of SO2 contains 2 moles of oxygen, and the molar mass of O is 16 g/mol. So, 25 moles x 2 moles = 50 moles of O, which is 50 moles x 16 g/mol = 800 g of O.