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5f2 2nh3 yields n2f4 6hf if you have 69.3 g nh3 how many grams of f2 are required for complete reaction?
Wiki User
∙ 15y ago
2.
Wiki User
∙ 15y ago
To find the grams of F2 required for the reaction, first calculate moles of NH3: 69.3 g NH3 / 17.03 g/mol = 4.07 moles NH3. From the balanced equation, 5 moles of NH3 react with 2 moles of F2, so you need 4.07 moles NH3 * (2 moles F2 / 5 moles NH3) * 38.0 g/mol = 30.6 g of F2 for complete reaction.
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∙ 14y agoHey Baby!!
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