answersLogoWhite

0


Best Answer

If a 10 microfarad capacitor is charged through a 10 ohm resistor, it will theoretically never reach full charge.

Practically, however, it can be considered fully charged after 5 time constants. One time constant is farads times ohms, so the time constant for a 10 microfarad capacitor and a 10 ohm resistor is 100 microseconds. Full charge will be about 500 microseconds.

User Avatar

Wiki User

14y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: A 10 microfard capacitor is charged through a 10 ohm resistor. How long will it take for the capacitor t fully charge?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Engineering

1 For a parallel plate capacitor which is being charged out What the incorrect statement is?

Energy stored in the capacitor does not enter it through the connecting wire through the space around the wires and plates of capacitor.


How long will it take a 0.047uF capacitor to charge 99 percent through a 100 k ohm resistor?

To find out the Question we also need two values,that is the value of the source voltage Vo & the value upto which they capacitor charged V. Then, V=Vo(1-e^(T/t)) where t=RC U can find out the Answer.


A capacitor is discharged through a 80 ohm resistor. The discharge current decreases to 29 percent of its initial value in 2 seconds. What is the value of the capacitor?

14 micro farads @ 1.4 seconds.. idk what it is at 2 seconds ;p


Does a charged capacitor block DC or AC or both?

It blocks DC or it wouldn't be charged. It passes AC through it to ground or it wouldn't filter. But in the early days charged electrolytic capacitors were used as rectifiers or AM detectors.


What happens to the output voltage if you fit a capacitor across the load resister?

first i will tell you that if we are taking output across resistor only:- if load is taken across resistor then both dc and ac currents will pass through the resistor.as we know current contains both dc and ac parts in many cases so we will get some other output... now if we add a capacitor across the resistor then all the ac component of current passes through capacitor and only dc part of current passes through the resisitor so we will get different output ..i will tell you why it happens ?? we know dc has zero frequency.. and we also know that Xc(reactance of capacitor)=1/(2*pi*frequency*c) now putting frequency =0 in above equation we get Xc =infinity.and that means capacitor's reactance is infinity so open circuited .thus no dc current passes through capacitor....... ........mrityunjay pandey (kiit university ,b.tech 2nd year)

Related questions

What to expect if a resistor is placed in a dc circuit with a capacitor?

when we replace the resistor with a capacitor ,the current will flow until the capacitor charge when capacitor will fully charged there is no current through the circuit because now capacitor will act like an open circuit. for more info plz E-mailt me at "zaib.zafar@yahoo.com"


Why do resistor voltage decrease while capacitor discharges?

The reason why resistor voltage decreases while a capacitor discharges is because the resistor acts like a source of electrical energy. As the capacitor discharges, it draws energy from the resistor, which causes the voltage across the resistor to decrease. This is because the capacitor is acting like a drain, and is taking energy out of the resistor, thus causing the voltage across the resistor to decrease. The resistor and capacitor work together in order to create a discharge circuit. This is done by connecting the capacitor to the resistor, and then to a voltage source. The voltage source supplies the energy to the resistor, and then the resistor transfers this energy to the capacitor. As the capacitor discharges, it takes energy from the resistor, which causes the voltage across the resistor to decrease. In order to understand this process better, it is important to understand the basics of Ohm's Law. Ohm's Law states that the voltage across a resistor is equal to the current through the resistor multiplied by the resistance. As the capacitor discharges, it takes energy from the resistor, which means that the current through the resistor decreases, and therefore the voltage across the resistor will also decrease.


Why the capacitor time period formula is given as t equals RC?

-- The quantity 'RC' has the physical dimensions of Time. -- If the capacitor is charging through a resistor, then 'RC' is the time it takes to charge up to (1 - 1/e) of the voltage it still has to go to become fully-charged. -- If the capacitor is discharging through a resistor, then 'RC' is the time it takes to discharge to 1/e of its present voltage. -- ' e ' is the base of natural logarithms, approximately 2.71828... -- 'RC' is called the 'time constant' of the resistor/capacitor combination.


Why don't capacitor discharge completely in an RC circuit?

Capacitors do not get "full" like a glass of water. The current into a capacitor is the rate of change of charge, so it's equal to C * dV/dt or something. If the voltage is constant, there's no current. If the voltage on both sides of the resistor is the same, there's no current through the resistor and hence into the capacitor, so that's the steady-state - what you call "full" - the capacitor charged to the supply voltage.


What is capacitive effect in antenna?

The capacitive effect is an element's opposition to a change in AC voltage. The resistor will develop a positively charged current at it flows through a capacitor. This will prevent a change in the initial voltage.


Why high value resistor should be connected in series with capacitor during charging or discharging process?

A resistor is used to limit current flow through a capacitor.If you did not use the resistor, you could potentially create large currents through the capacitor, damaging it. Capacitors do have current limit ratings - check the specification sheet for the capacitor.Also, in the case of an electrolytic capacitor, if it is generally in a discharged state then it is necessary from time to time to reform it. That process involved slowly charging it, i.e. through a resistor, and then letting it discharge by itself with no or little load. The resistor protects both the capacitor and the voltage source in the case that the capacitor might be shorted.


1 For a parallel plate capacitor which is being charged out What the incorrect statement is?

Energy stored in the capacitor does not enter it through the connecting wire through the space around the wires and plates of capacitor.


How much time constants to charge or discharge a capacitor?

Theoretically, forever, because as the voltage on the capacitor approaches the source voltage, the available current to charge the capacitor approaches zero.In practice, however, it simply depends on what you call "charged".In the simple example of a capacitor being charged from a voltage source in series with a resistance, the voltage is given by ...VT = Vs (1 - e -T/RC)... so, if your definition of "charged" is 99% of VT then T would have to be 5 RC's or 5 time constants.If a resistor is connected in series with the capacitor forming an RC circuit, the capacitor will charge up gradually through the resistor until the voltage across the capacitor reaches that of the supply voltage. The time called the transient response, required for this to occur is equivalent to about5 time constantsor5T. This transient response timeT, is measured in terms ofτ= R x C, in seconds, whereRis the value of the resistor in ohms andCis the value of the capacitor in Farads. This then forms the basis of an RC charging circuit were5Tcan also be thought of as"5 x RC".


What is the role of capacitor in an astable multivibrator?

The capacitor charges up with the current flowing through a resistor. The time taken is well defined by the capacitance and the resistance, and these components control the frequency.


Why does a fully charged capacitor show infinite resistance?

The voltage-current relationship for a capacitor is i = C dv/dt, where i is the current flowing through, C is the capacitance and dv/dt is the time rate change of the voltage across that capacitor. So, when a capacitor is fully charged, the voltage no longer changes with time (the derivative, dv/dt, is now 0). As can be seen from the equation, the current would therefore be 0. Anything with 0 current flowing through is an open circuit, and can be treated like a resistor with infinite resistance (in models, anyway). Practically speaking, capacitors aren't this perfect, but you will still have an extremely high resistance once fully charged (voltage changes negligibly after charging).


Why do you connect a diode in parallel to a capacitor?

1. bec the capacitor not allow the current to pass through it after it has charged & it charged in no time ex:(10^-4 second). 2. because it is necessary to avoid wrong polarity by shorting the terminals of the capacitor and tripping the fuse.


How do you hook up a 500k micro farad?

A capacitor of 0.5 Farad should have screw or spade terminals, with clear polarity markings. POLARITY IS EXTREMELY IMPORTANT! The "-"/negative terminal needs to be connected to ground, while the +/positive is connected to the vehicle power. Reversing polarity will cause the capacitor to explode. You will also want to charge the capacitor initially through a resistor to prevent blowing a fuse/breaker. A 100 ohm resistor will keep the current below roughly 100mA during charging. Let capacitor charge 15-20 minutes if it is a fully discharged capacitor. Once charged remove resistor and connect power cable directly to capacitor. Once charged, large capacitors can dump large amounts of current, creating a fire hazard! Ensure all connections are well insulated once connected, and the power cable is sized to match the power of the component.