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The voltage-current relationship for a capacitor is i = C dv/dt, where i is the current flowing through, C is the capacitance and dv/dt is the time rate change of the voltage across that capacitor. So, when a capacitor is fully charged, the voltage no longer changes with time (the derivative, dv/dt, is now 0). As can be seen from the equation, the current would therefore be 0. Anything with 0 current flowing through is an open circuit, and can be treated like a resistor with infinite resistance (in models, anyway). Practically speaking, capacitors aren't this perfect, but you will still have an extremely high resistance once fully charged (voltage changes negligibly after charging).

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Q: Why does a fully charged capacitor show infinite resistance?
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What would happen to the current flow in a dc circuit when the capacitor is fully charged?

A capacitor charge as a time constant of R resistance C capacitance in ufd and it is defined as 63% for one time constant for the constant voltage source. Electronic engineers assume that a capacitor is fully charged by a 5 times constant. however mathematically speaking it will never be fully charged for obvious reasons. Therefore the answer is current will never stop/


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When a circuit consists of a capacitor and a resistor in series with a voltage source and the voltage across the resistor becomes zero then the capacitor is?

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How long will it take to fully charge a capacitor in a series RC ciRCuit with a 6microfarad capacitor 2Kilohm resistor and 141 volt supply?

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