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A 3 V battery is connected in series with a resistor and an inductor The series circuit has a time constant of 532ms and the maximum current is 262 mA What is the value of the inductance?
Beth05202
The final current is E/R = 0.262 = 3/R.
R = 3/0.262 ( = 11.45 ohms ).
The time constant is RL = 0.532.
L = 0.532 / R = (0.532) / (3/0.262) = (0.532) (0.262) / 3
= 46.46 millihenrys (rounded)
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∙ 14y ago
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