10 Ohms.
That depends ... in a very interesting way ... on whether they are connected in series or in parallel. -- If the resistors are in series, then the total resistance increases when you add another resistor, and it's always greater than the biggest single one. -- If the resistors are in parallel, then the total resistance decreases when you add another resistor, and it's always less than the smallest single one.
To find the missing resistor in a series circuit, first calculate the total resistance using the formula ( R_{total} = R_1 + R_2 + R_3 + ... + R_n ), where ( R_1, R_2, R_3, ) etc., are the known resistors. Rearrange the equation to solve for the missing resistor ( R_x ) as ( R_x = R_{total} - (R_1 + R_2 + ... + R_n) ). If you know the total voltage and current in the series, you can also use Ohm’s Law (( V = I \times R )) to find the total resistance and then determine the missing resistor.
A: If you know the total resistance and total voltage then you know total current flow for the circuit, this current will be same for every resistor in series however the voltage drop will change for each resistor . So measuring the voltage drop across the resistor in question and divide by the total current will give you the resistor value.
In a series circuit, the total voltage supplied by the source is divided among the resistors based on their resistance values. According to Ohm's Law (V = IR), a resistor with a larger resistance will have a larger voltage drop when the same current flows through it. Therefore, the resistor with the highest resistance in a series circuit will indeed experience the largest voltage drop. This is because the voltage drop across each resistor is directly proportional to its resistance.
Resistances in series act just as if they were one single resistor. The value of the single resistor is the sum of the individual resistors connected in series ... Ra + Rb + Rc etc. When several resistors are in series, the effective total is greater than the biggest one. Resistance in parallel act just as if they were one single resistor. The reciprocal of the value of the single resistor is the sum of the reciprocals of the individual resistors connected in parallel ... Total effective resistance = 1 divided by (1/Ra + 1/Rb + 1/Rc + etc.) When several resistors are in parallel, the effective total is less than the smallest one. Once you figure out the effective value of the series- or parallel-combination of many resistors, you handle them as if they were one single resistor, and you can work with the voltage and current: Current through any resistance = (Voltage across it) divided by (its resistance).
2
If the resistors are in series, then the total resistance is simply the sum of the resistances of each resistor.
the voltage across that resistor will increase if it is in series with the other resistors. the current through that resistor will increase if it is in parallel with the other resistors.
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In a series circuit, if one resistor is replaced with a resistor of lower resistance, the total resistance in the circuit decreases. This leads to an increase in the overall current flowing through the circuit.
Two resistors connected in parallel are 1/2 the sum of their resistance. The resistance of two resistors connected in series is the sum of their resistance. For example: The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in parallel is 100+200 divided by 2 = 150 ohms. The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in series 100+200= 300 ohms.
That depends ... in a very interesting way ... on whether they are connected in series or in parallel. -- If the resistors are in series, then the total resistance increases when you add another resistor, and it's always greater than the biggest single one. -- If the resistors are in parallel, then the total resistance decreases when you add another resistor, and it's always less than the smallest single one.
To find the missing resistor in a series circuit, first calculate the total resistance using the formula ( R_{total} = R_1 + R_2 + R_3 + ... + R_n ), where ( R_1, R_2, R_3, ) etc., are the known resistors. Rearrange the equation to solve for the missing resistor ( R_x ) as ( R_x = R_{total} - (R_1 + R_2 + ... + R_n) ). If you know the total voltage and current in the series, you can also use Ohm’s Law (( V = I \times R )) to find the total resistance and then determine the missing resistor.
A: If you know the total resistance and total voltage then you know total current flow for the circuit, this current will be same for every resistor in series however the voltage drop will change for each resistor . So measuring the voltage drop across the resistor in question and divide by the total current will give you the resistor value.
The total resistance in a circuit with series resistors is the sum of the individual resistances. When more resistors are added in series, the total resistance increases because the current has to pass through each resistor, making it harder for the current to flow.
Resistance in a series circuit is added by simply connecting resistors end-to-end. This results in the total resistance being the sum of the individual resistances. The current passing through each resistor in a series circuit remains the same.
In a series circuit, the total voltage supplied by the source is divided among the resistors based on their resistance values. According to Ohm's Law (V = IR), a resistor with a larger resistance will have a larger voltage drop when the same current flows through it. Therefore, the resistor with the highest resistance in a series circuit will indeed experience the largest voltage drop. This is because the voltage drop across each resistor is directly proportional to its resistance.