You'll get a reading on the ammeter showing 15 mA
If you have three 100 ohm resistors, and you want an equivalent resistor of 66.7 ohms, put two resistors in series, and then parallel the third resistor across the first two. Resistors in series: R1 + R2 Resistors in parallel: R1 * R2 / (R1 + R2) This example: Two 100 ohm resistors in series: 100 + 100 = 200 A 100 ohm resistor in parallel with a 200 ohm resistor: 100 * 200 / (100 + 200) = 66.7
a) Put 2 of the resistors in series to make a 200 ohm resistor. Then put the 100, 100, and 200 ohm resistors in parallel for 40 ohms. b) Put 2 resistors in parallel for 50 ohms. Put the 50, 100, and 100 ohm resistors in series for 250 ohms. c) Put 2 resistors in parallel for 50 ohms. Repeat with other 2 resistors. Put the two 50 ohm resistors in series for 100 ohms. This configuration can withstand 4 times the wattage of each individual resistor.
What would the measured ohms be for two 100 ohm resistors wired in series? Two 100 ohm resistors wired in series measure 200 ohms.
Add the two together. For instance, two 100 ohm resistors in series have a total resistance of 200 ohms.
You need to calculate the equivalent resistance. For instance, if the three resistors are connected in series, simply add all the resistance values up. Then, you calculate the current (in amperes) using Ohm's Law (V=IR); that is, you need to divide the voltage by the resistance.
total resistance is each resistor added together
If you have three 100 ohm resistors, and you want an equivalent resistor of 66.7 ohms, put two resistors in series, and then parallel the third resistor across the first two. Resistors in series: R1 + R2 Resistors in parallel: R1 * R2 / (R1 + R2) This example: Two 100 ohm resistors in series: 100 + 100 = 200 A 100 ohm resistor in parallel with a 200 ohm resistor: 100 * 200 / (100 + 200) = 66.7
a) Put 2 of the resistors in series to make a 200 ohm resistor. Then put the 100, 100, and 200 ohm resistors in parallel for 40 ohms. b) Put 2 resistors in parallel for 50 ohms. Put the 50, 100, and 100 ohm resistors in series for 250 ohms. c) Put 2 resistors in parallel for 50 ohms. Repeat with other 2 resistors. Put the two 50 ohm resistors in series for 100 ohms. This configuration can withstand 4 times the wattage of each individual resistor.
What would the measured ohms be for two 100 ohm resistors wired in series? Two 100 ohm resistors wired in series measure 200 ohms.
the 87 didn't have resistors it has a computer behind the battery.
Two resistors connected in parallel are 1/2 the sum of their resistance. The resistance of two resistors connected in series is the sum of their resistance. For example: The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in parallel is 100+200 divided by 2 = 150 ohms. The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in series 100+200= 300 ohms.
Add the two together. For instance, two 100 ohm resistors in series have a total resistance of 200 ohms.
The question lacks a very important piece of information: In what configuration are the resistors connected ? Series ?? Parallel ??? Some combination of series and parallel ????Five resistors: 1, 1, 1, 100, 101 ohms respectively.If all 5 are in series, the equivalent is (1 + 1 + 1 + 100 + 101) = 204 ohms.If all 5 are in parallel, the equivalent is the reciprocal of (1 + 1 + 1 + 1/100 + 1/101)= 1 / (3.0199) = 0.331137 ohms (rounded)
Resistance in series adds together. two 100 ohm resistors in series are equivalent to one 200 ohm resistor. to make an equation out of it ( even though it is simple) you can say: Rtotal=R1+R2+R3...+Rn
Two equal resistors in a series circuit will always split the supply voltage in half. The digital volt meter is a red herring.
If two 1-ohm resistors are connected in parallel, their resistance is 0.5 ohms. If they are connected in series, their resistance is 2 ohms. It is not possible to connect only two resistors in series parallel.
The net effective resistance of resistors in series is the sum of the individuals.Combined resistance = (100,000,000) + (10) = 100,000,010Ωhms.