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An object would need to start at about 25 miles per second in order to escape Earth's gravity.

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Q: A body can escape the gravitational pull of the earth if it is thrown up with a velocity of?
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You say that the escape velocity is the one required to escape the earth's gravitational speed then we say the satellites stay in orbits because of the earth's gravitational speed how does that ha?

Satellites are traveling at less than escape velocity. (roughly, orbital velocity is about 7 tenths of escape).


What is anEscape Velocity?

Velocity sufficient for a body to escape from a gravitational attraction without acceleration. Earth has an escape velocity of 11.19 kmsec-1 .


What will a rocket do if it reaches escape velocity?

It will get out of Earth's gravitational pull and can no longer be forced back towards Earth.


Why do objects that are thrown or shot follew a curved path?

Because the gravitational force from Earth will change the velocity.


How much speed required to go against gravity?

Assuming there is no air resistance, if an object starts at a speed of 11.2 km/sec, it can escape the gravitational field of Earth. This "escape velocity" is different for different planets, moons, etc.Assuming there is no air resistance, if an object starts at a speed of 11.2 km/sec, it can escape the gravitational field of Earth. This "escape velocity" is different for different planets, moons, etc.Assuming there is no air resistance, if an object starts at a speed of 11.2 km/sec, it can escape the gravitational field of Earth. This "escape velocity" is different for different planets, moons, etc.Assuming there is no air resistance, if an object starts at a speed of 11.2 km/sec, it can escape the gravitational field of Earth. This "escape velocity" is different for different planets, moons, etc.


What does the term 'escape velocity' mean?

Escape velocity is what a moving body has to achieve in order not to be pulled back down to the planet. For Earth it is about 7 miles per second.


The speed and direction a rocket must have to break away from a planet's gravitational pull?

The speed is called the escape velocity. An object travelling at the Earth's escape velocity will never return to Earth because as it moves away, and decelerates under the Earth's gravity, the force pulling it back (its weight) is also reducing and if it is above the escape velocity it will escape altogether.


A rocket that moves upward from earth's surface at escape velocity will?

Escape the earth's gravitational pull and continue out into space. However, a rocket does not need to be launched at the escape velocity as it can continue to accelerate as it climbs. A gun projectile would need to be fired with the escape velocity. In a perfect system with only the projectile and the Earth: If the projectile is fired with the exact escape velocity it will travel to infinity away from the Earth. Upon reaching infinitely far away from Earth the projectile would have zero velocity. All of its kinetic energy (movement) would be transferred to potential energy.


Force required to break from Earths atmosphere?

To be able to escape earth's atmosphere you need to achieve a velocity that is great enough to achieve sufficient energy to escape the earth's gravitational field strength.


What is the boundary above which objects thrown up do not reach the Earth called?

The limit is not so much a distance from Earth, but rather a velocity - called the escape velocity. (roughly 25000 mph) /Brian W


Why must spacecraft reach escape velocity to be able to go to space?

a slower speed will not overcome the gravitational pull of the Earth. It would fall back to Earth.


How fast do you need to go to escape earth's gravity?

The speed or velocity an object needs to escape from the gravitational field of a planet is called "Escape Velocity" In other words, the amount of kinetic energy needed to overcome the gravitational field. The expression is given in 1/2mv^2 - GMm/r (m= mass of object trying to overcome gravitational field) M(mass of the planet) V(Escape Velocity) G(universal constant which = 6.67E-11) r(distance from surface of planet or w/e) when you derive that formula, you will find that the velocity needed is: V= *square root of: 2GM/r