40volt
Current flows in loops, voltage drops across elements. With relation to current, what flows in, must flow out, so no, current is not dropped across a resistor, it flows through a resistor and voltage is dropped across the resistor.
No. If a voltage is applied across a resistor, a current flows through it.
No current flows when the the voltage is zero.
Normally through the resistor's internal construction. It flows through any part of the resistor that has low resistance- be it anywere. And then there's this. It might be that one should consider that current flows through a resistor and voltage is dropped across a resistor. Perhaps this is where the question began. The former is fairly straight forward. The latter can be vexing. Voltage is said to be dropped across a resistor when current is flowing through it. The voltage drop may be also considered as the voltage measureable across that resistor or the voltage "felt" by that resistor. It's as if that resistor was in a circuit by itself and hooked up to a battery of that equivalent voltage.
33V
V = (I) x (R) = 2 x 12 = 24 volts
True
Use Ohm's Law, i.e., V=IR here, V=voltage I=current R=resistance
The answer is 6 ohms x 3 amps which is 18 v.
Current moving through a resistor causes it to heat up because of the flowing electrons bumping into the atoms in the resistor.
The capacitive effect is an element's opposition to a change in AC voltage. The resistor will develop a positively charged current at it flows through a capacitor. This will prevent a change in the initial voltage.
The Bleeder current.