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A mixture of NaCl and NaBr has a mass of 2.03 g and is found to contain 0.76 grams of Na What is the mass of NaBr in the mixture?
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∙ 10y ago
.22352 grams
Wiki User
∙ 10y ago
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How many grams of NaBr are contained in 75.0 mL of a 1.5 M NaBr solution?
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
How many molecules of NaBrO3 are in a 34.5 gram sample of NaBrO3?
34.5 grams NaBrO3 (1 mole NaBrO3/150.89 grams)(6.022 X 10^23/1 mole NaBrO3) = 1.38 X 10^23 molecules of sodium bromate
What reactant is limiting if 3000 cm3 of Cl2 at STP react with a solution containing 25 grams of NaBr?
Cl2 + 2NaBr => Br2 + 2NaCl One mole Cl2 reacts with 2 moles NaBr Cl2 = 71 NaBr = 102.9 Molar volume = 22.414 L/mole for ideal gas @STP 3L Cl2 = 3/22.414 = 0.1338 mole 25g NaBr = 25/102.9 = 0.2430 mole 0.1338 moles Cl2 requires 0.2676 moles NaBr for complete reaction The NaBr is the limiting reagent
Is nabr a acid?
No, NaBr is a neutral salt.
Is NaBr a acid or base or salt?
NaBr is a salt.
How many grams of NaBr are contained in 75.0 mL of a 1.5 M NaBr solution?
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
What is the molar mass of NaBr?
Sodium bromide (NaBr) has a weight of 102.89 grams per mole. Determining the mass of NaBr in a mixture can be calculated if the constituent weights of all the others are known. The total masses of the knows can be subtracted by the overall weight to isolate the mass of NaBr.
What volume of 0.256 M sodium bromide contains 18.7 grams of bromide?
Need moles sodium bromide first. 18.7 grams NaBr (1 mole NaBr/102.89 grams) = 0.1817 moles NaBr =====================Now, Molarity = moles of solute/Liters of solution 0.256 M NaBr = 0.1817 moles NaBr/X Liters Liters = 0.1817/0.256 = 0.7098 Liters -------------------------( you do sigi figis )
Is sodium bromide an element compound or mixture?
Sodium bromide (NaBr) is a compound.
How many grams of NaBr are contained in 105ml of a 1.90M NaBr solution?
Following the definitiion of molarity, 1.90 M = (weight in g) / (102.894 * 0.105) So weight of NaBr = 1.90 * 102.894 * 0.105 = 20.53 g
How many molecules of NaBrO3 are in a 34.5 gram sample of NaBrO3?
34.5 grams NaBrO3 (1 mole NaBrO3/150.89 grams)(6.022 X 10^23/1 mole NaBrO3) = 1.38 X 10^23 molecules of sodium bromate
What reactant is limiting if 3000 cm3 of Cl2 at STP react with a solution containing 25 grams of NaBr?
Cl2 + 2NaBr => Br2 + 2NaCl One mole Cl2 reacts with 2 moles NaBr Cl2 = 71 NaBr = 102.9 Molar volume = 22.414 L/mole for ideal gas @STP 3L Cl2 = 3/22.414 = 0.1338 mole 25g NaBr = 25/102.9 = 0.2430 mole 0.1338 moles Cl2 requires 0.2676 moles NaBr for complete reaction The NaBr is the limiting reagent
Is nabr a acid?
No, NaBr is a neutral salt.
How many grams of sodium does a 5.35 g sample of sodium bromide contain?
All you really need here is a ratio of molar masses, ie molar mass of Na/molar mass of NaBr So look at your periodic table and is says: Na = 23g/mol Br = 80g/mol therefore NaBr = 103g/mol so from this, you actually know a percentage of Sodium to Bromine, correct me if I'm wrong, someone else please but just take: (23g/mol)/103g/mol = 22.3% of you NaBr is actually Na, so take 5.35g * 0.223 and you get: 1.19g of Na in your NaBr Hope that helps. Cheers
Is NaBr a acid or base or salt?
NaBr is a salt.
What is the melting point of NaBr?
The melting point of NaBr is 747 oC.
NaBr salt acid or base?
Sodium bromide (NaBr) is a salt.
