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A resistor of 25ohm is connected in series with capacitor of 45microfarad calculate impedance and current taken from 240volts 50Hz supply please tell how to solve or formulas please?
Phirmiliengay
First, you will need to convert to the frequency domain.
ZR = R; Zc = 1/(jwc); ZL = jwL; w = 50Hz*2pi = 100pi
ZR = 25 ohm; Zc = -j80 ohms; v = 240*cos(100pi + 0)V
Second, combine the impedances, in series.
Zeq = ZR + Zc = 25-j80 ohms
Finally use Ohm's law to find the current. v = i*Z
i = 240 V / 25-j80 ohms = 2.9*e^(j73)A
2.9*e^(j1.28) has a magnitude of 2.9A and a phase of 73 degrees.
Now, you may need to convert back to the time domain.
i = 2.9cos(100pi + 73)A
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∙ 14y ago
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