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A volume of 90.0 ml of aqueous koh was titrated against standard solution of h2so4 what is the molarity of the koh solution if 20.7 ml of 1.50 m h2so4 was needed?
Wiki User
∙ 12y ago
Use the formula C1(V1) = C1(V2) to find the unknown concentration.
Here, V1 = 20ml and V2 = 33.86ml.
Also, C2 is 0.1368M
Now plug in these values to find V1
Therefore we have:
20ml(V1) = (0.1368)(33.86)
Therefore, V1 = 0.2316M
The a 0.2316M solution of H2SO4 was required for the neutralization reaction
Wiki User
∙ 14y ago
Wiki User
∙ 12y agoM (molarity) X V (volume) = M (molarity) X V (volume)
1.50 M X 20.7 ml = M X 90.0 ml
Molarity = .345 M
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