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Adding a DC source to a square wave signal will alter the base line of the wave without changing the peak-to-peak value.

For example, if a square wave has a +4V baseline and a +2VDC source is introduced, the resulting square wave will have a +6V baseline. This of course will also affect the high and low peaks of the signal. Assuming that our example has a high peak of +9V and a low peak of -1V (with a total of 10V peak-to-peak), the added +2VDC source would result in a high peak of +11V and a low peak of +1V; however, the total peak-to-peak value remains unchanged at 10V peak-to-peak.

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Q: Adding a DC source to a square wave signal?
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