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In a series circuit, resistances can be added directly whereas if they were wired in paralell you would add their inductances denoted by G instead of R and then take the reciprocal 1/Gtotal to find equivalent resistance. G = 1/R.

Series Ex.

23 ohms + 5 ohms = 28 ohms. and due to Ohms law V (volts) = I (amps) * R (ohms)

so I = V/R = 44/28 = 1.57 amps

Paralell ex.

Rtotal = 1/((1/23)+(1/5)) = 1/(.0435+.2) = 1/.2435 =4.1 ohms

therefore=> I = V/R = 44/4.1 = 10.7 amps.

Note this is the total current drawn from the power supply. In reality each resistor draws its portion of current where the lower resistance draws higher current and vice versa.

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Q: An R equals 23.0-Ω lamp and a 5.0-Ω lamp are connected in series and placed across a potential difference of V equals 44.0 Vwhat is the current of the circuit?
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