2Br is two separate bromine atoms.
Br2 is a bromine molecule, consisting of two bromine atoms bonded together.
H2 + Br2 --> 2HBr.
I don't now
Bromine is the oxidizing element.
MgBr2 + Cl2 yields MgCl2 + Br2 is an example of an anionic single replacement chemical reaction.
C6H6O + Br2
Br2 + Zn ----> ZnBr2
2 Na + Br2 --> 2 NaBr
Is this the reaction you mean 2Br Cl2--->Br2 2Cl This can be happen.Equation in your question cannot be happened
How do you draw and electron cloud for 2Br and for Br2
2I- + Br2 ---> I2 + 2Br-
Net ionic: Br2 + 2I- -> 2Br- + I2
2Br^-(aq)-->Br2(l)+2e
Bromine is the oxidizing element.
S in (SO4)-2 has a charge of +6, in SO2 S has a charge of +4. To go from +6 to +4 you must gain two electrons. The (SO4)-2 is reduced (reduction is gaining electrons). Therefore it reduces the 2br-, so (SO4)-2 is the reducing agent
1 mole Br2 = 159.808g Br2 = 6.022 x 1023 molecules Br2 4.89 x 1020 molecules Br2 x 1mol Br2/6.022 x 1023 molecules Br2 x 159.808g Br2/mol Br2 = 0.130g Br2
When analyzing the possible reaction between ZnCl2 and Br2 you must first compare the activities of Chlorine and Bromine.
MgBr2 + Cl2 yields MgCl2 + Br2 is an example of an anionic single replacement chemical reaction.
No, it is covalent as it contains two atoms of the same element, meaning no difference in electronegativity.
Br2 + H20 ===> HBr + HOBr