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There are forces acting on the car. They are just equal to the force of the car acting on the force. In example, gravity is acting on the car, but the car is pushing back equally. Therefore, the car doesn't move.

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Q: Are there forces acting on a car that is at rest xy?
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Is an xy axis a frame of reference?

Yes.


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Newton studied the relationship of objects and forces acting on them. Objects move because of various forces are applied to them. These Laws are: First law: A particle will stay at rest or continue at a constant velocity unless acted upon by an external unbalanced net force. Second law: The net force on an object is equal to the mass of the object multiplied by its acceleration. Mathematically F = ma: Third law: Every action has an equal and opposite reaction. Now the question is "What is move?" We can intuitively understand that locations in space are different from each other. At the macro scale (the Universe we observe) that is true. Objects relate to each other in way that can be described as in front or behind, higher or lower, left or right of (or some combination of these terms) This relation can be shown easily on a three dimensional graph using XY and Z coordinates. Objects can easily be understood to be differently placed in time - it used to be here, now it's there. All in all there are many dimensions that an object can move through. Moving is therefore the translation of an object to different location over time. Strangely enough at the very small scale of the Universe objects don't seem to be any place in particular. We can only provide a probable location. Using the electron again, it might not be anywhere in a probability density cloud around a nucleus. So it is difficult to say if it is "moving" or not.


Find the angle formed by highways xy and xz if x is 6 km from y y is 4 km from z and x is 5 km from z?

We have a triangle with side lengths 6, 4, and 5 (the units are irrelevant). We want to know the size of the angle A formed between the sides of length 6 and 5. Use the cosine rule: 42 = 62 + 52 - 2(6x5)cosA 16 = 36 + 25 - 60cosA 16 = 61 - 60cosA 60cosA = 45 cosA = 0.75 So, A = arccos(0.75) or about 41.4 degrees, or 0.72 radians.