No, because their polarities are too far apart. You can circumvent this by adding a solvent that has a polarity in between these two solvents, e.g. ethanol, methanol, dioxane, dimethylformamide or dimethylsulfoxide.
No the two are immiscible and trichloroethane is denser than water
Yes, H20 and CH3OH are miscible.
Co2 + 3h2 gives ch3oh + h2o
1: Yes, Two polar compounds are miscible. 2. No, CBr4 is non polar, while H2O is polar; immiscible. 3. No, Cl2 is non polar, while H2O is polar: immiscible.
a. KCl in water b. CH3OH in H2O c. CH2Cl2 in benzene
CuO + CH3OH --> HCHO + Cu + H2O
H2O is very slightly soluble in CH2CL2 but H2O is hydrophillic and CH2Cl2 is hydrophobic therefore the two molecules dont react or bond properly resulting in a two phase solution of an aquous and organic layer containg a very small percentage of the H2O.
Ch3oh
Co2 + 3h2 gives ch3oh + h2o
CH3OH is the chemical formula for methanol. Methanol is miscible with water in ALL proportions. It DOES dissolve or mix with water.
No. Hydrocarbons are not miscible in water.
1: Yes, Two polar compounds are miscible. 2. No, CBr4 is non polar, while H2O is polar; immiscible. 3. No, Cl2 is non polar, while H2O is polar: immiscible.
a. KCl in water b. CH3OH in H2O c. CH2Cl2 in benzene
CH3OH + NH3 → CH3NH2 + H2O 32 g of methanol reacts with 17.0 g ammonia 21 g of CH3OH react with 11.0 g NH3
CuO + CH3OH --> HCHO + Cu + H2O
As with any combustion reaction you need to include oxygen. The full equation for methanol combustion is: CH3OH + 2 O2 --> CO2 + 2 H2O
its balanced
NaOH + CH3OH --> CH3ONa + H2O Evaporate the solution to dryness, add more CH3OH and evaporate to dryness. you can repeat a few times to ensure the remaining solid is sodium methoxide
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH