No, because their polarities are too far apart. You can circumvent this by adding a solvent that has a polarity in between these two solvents, e.g. ethanol, methanol, dioxane, dimethylformamide or dimethylsulfoxide.
To balance the equation CO2 + H2 ➝ CH3OH, you would need to first balance the carbon atoms, then the hydrogen atoms, and finally the oxygen atoms. In this case, the balanced equation would be: CO2 + 3H2 ➝ CH3OH + H2O.
Yes, both ch3ch2ch2ch2ch3 and ch3ch2ch2ch2ch2ch3 are miscible since they are both alkanes with similar intermolecular forces. CBr4 and H2O are immiscible because CBr4 is nonpolar while H2O is polar, resulting in different intermolecular forces that prevent them from mixing. Cl2 and H2O are immiscible because Cl2 is a nonpolar molecule while H2O is polar, leading to differences in intermolecular forces that hinder their ability to mix.
For KCl in water, the interaction is ion-dipole, which is a strong interaction. For CH2Cl2 in benzene, the interaction is dipole-dipole, which is weaker than ion-dipole. For C6H6 and CH3OH in H2O, the interaction is hydrogen bonding, which is stronger than dipole-dipole. Therefore, rank from weakest to strongest would be: CH2Cl2 in benzene, C6H6 and CH3OH in H2O, KCl in water.
There is no easy method to balancing equations, you just have to check each side of the equation to ensure that it has an equal number of each atom: 2K + 2H2O --------> H2 + 2KOH
H2O is very slightly soluble in CH2CL2 but H2O is hydrophillic and CH2Cl2 is hydrophobic therefore the two molecules dont react or bond properly resulting in a two phase solution of an aquous and organic layer containg a very small percentage of the H2O.
To balance the equation CO2 + H2 ➝ CH3OH, you would need to first balance the carbon atoms, then the hydrogen atoms, and finally the oxygen atoms. In this case, the balanced equation would be: CO2 + 3H2 ➝ CH3OH + H2O.
Methanol and water do not react they just form a very stable solution.
Yes, both ch3ch2ch2ch2ch3 and ch3ch2ch2ch2ch2ch3 are miscible since they are both alkanes with similar intermolecular forces. CBr4 and H2O are immiscible because CBr4 is nonpolar while H2O is polar, resulting in different intermolecular forces that prevent them from mixing. Cl2 and H2O are immiscible because Cl2 is a nonpolar molecule while H2O is polar, leading to differences in intermolecular forces that hinder their ability to mix.
Among the liquids mentioned, H2O (water) is the best conductor of electricity. This is because water contains ions that allow for the flow of electric current. Methanol (CH3OH) and carbon tetrachloride (CCl4) are poor conductors of electricity because they do not dissociate into ions in the same way as water does.
The structural formula of C3H7COOH is CH3CH2COOH (propionic acid). The structural formula of CH3OH-C3H7COOCH3 is CH3OH + CH3CH2COOCH3 (methyl propionate). H2O (water) is produced when these two compounds react together.
For KCl in water, the interaction is ion-dipole, which is a strong interaction. For CH2Cl2 in benzene, the interaction is dipole-dipole, which is weaker than ion-dipole. For C6H6 and CH3OH in H2O, the interaction is hydrogen bonding, which is stronger than dipole-dipole. Therefore, rank from weakest to strongest would be: CH2Cl2 in benzene, C6H6 and CH3OH in H2O, KCl in water.
No, C4H10 (butane) and H2O (water) are not miscible because they have different polarities. Butane is a nonpolar hydrocarbon while water is a polar molecule. As a result, they do not mix together and will form separate layers.
When methanol (CH3OH) reacts with sulfuric acid (H2SO4), it forms dimethyl ether (CH3OCH3) and water (H2O) as products. This reaction is known as the dehydration of methanol.
As with any combustion reaction you need to include oxygen. The full equation for methanol combustion is: CH3OH + 2 O2 --> CO2 + 2 H2O
The balanced equation between ethanoic acid (CH3COOH) and methanol (CH3OH) to form methyl acetate (CH3COOCH3) is: CH3COOH + CH3OH -> CH3COOCH3 + H2O.
its balanced
CH4 + H2O -> CH3OH + CH3OCH3 Does not balance; Each compound on the product side has one Carbon and Hydrogen atom, so there must be one methane and water molecule per each DME and methanol molecule So the hydrogens are then impossible to balance as one methane molecule has four hydrogens add that to the two hydrogens from each water molecule thats 6. Methanol has four hydrogens - bearing in mind that 6 would be produced per molecule The reaction hence cannot be balanced 2 CH3OH -> H2O + CH3OCH3 is the sythesis of DME from its consituents, maybe there was a transcription error somewhere.