C program for swap two numbers without using temporary variables?

Answer 1

Using a temporary variable:

#include<stdio.h>

#include<conio.h>

void main()

{

int a,b,temp;

clrscr():

printf("Enter the first number a\n");

scanf("%d",&a);

printf("Enter the second number b\n");

scanf("%d",&b);

printf("Before swapping a=%d b=%d",a,b);

temp=a;

a=b;

b=temp;

printf("The swapped values are: a=%d b=%d",a,b);

getch();

}

Without using a temporary variable:

#include<stdio.h>

#include<conio.h>

void main()

{

int a,b;

clrscr();

printf("Enter the first number a\n");

scanf("%d",&a);

printf("Enter the second number b\n");

scanf("%d",&b);

printf("Before swapping a=%d b=%d",a,b);

a=a+b;

b=a-b;

a=a-b;

printf("The swapped values are: a=%d b=%d\n");

getch();

}

Answer 2

int num1=15;

int num2=25;

int temp;

temp=num1;

num1=num2;

num2=temp;

int num1=15;

int num2=25;

num1=num1+num2;

num2=num1-num2;

num1=num1-num2;

Answer 3

#include; main() {int a,b; printf("enter the value of a"); scanf(%d%,&a); printf("enter the vaule of b"); scanf(%d%,&a); a=a+b b=a-b a=a-b printf("%d%%d%",a,b);}

Answer 4

A ^= B;

B ^= A;

A ^= B;