Potassium Sulfide - K2S
2 Potassium
1 Sulfur
Potassium = 39 grams per mole
Sulfur = 32 grams per mole
Add up the total mass - 2 K's and 1 S:
2(39) + 1(32) = 110 grams/mole
Now just make sure the units cancel so that you can multiply or divide out the mole unit
3.3 mole K2S x 110 grams K2S/mole
mole unit cancels and you're left with 363 grams K2S
You did not describe the amount of potassium bicarbonate amount in grams in your question. But if you are about 1 gram of potassium bicarbonate it will be 0.0099 moles in one gram of potassium bicarbonate. 0.0199 moles in 2 grams of potassium bicarbonate.
The formula mass of potassium sulfide, K2S is 2(39.1)+32.1=110.3 1 mole of potassium sulfide has a mass of 110.3g Mass of 3.3mol of K2S = 3.3 x 110.3 = 364g
224 grams of Oxygen will be in 2 moles of Potassium dichromate.
This mass is 347,67 for KMnO4.
there are two moles produced in potassium nitrate.
You did not describe the amount of potassium bicarbonate amount in grams in your question. But if you are about 1 gram of potassium bicarbonate it will be 0.0099 moles in one gram of potassium bicarbonate. 0.0199 moles in 2 grams of potassium bicarbonate.
34,7 moles of potassium 1 356,7 g.
The formula mass of potassium sulfide, K2S is 2(39.1)+32.1=110.3 1 mole of potassium sulfide has a mass of 110.3g Mass of 3.3mol of K2S = 3.3 x 110.3 = 364g
In one mole of potassium dichromate, there seven moles of oxygen. This means in two moles of K2Cr2O7, there are 14 moles of O, or 7 Moles of O2, which equals 224 grams.
The molecular weight of potassium nitrate (KNO3) is 101.1 grams/mole.K = 39.1 + N = 14.0 + O = 3*16.0 = 101.1Now divide 6.5 by 101.1 to calculate # of moles => 0.064 moles KNO3
224 grams of Oxygen will be in 2 moles of Potassium dichromate.
224 g are in two moles of potassium dichromate.
25,3 moles of potassium sulfate hva a mass of 4,4409 kg.
45/94.2 is 0.4777 moles
3.99 or 4
About 0.013
871 grams