(7.6 g NaCl) (moles NaCl/58.44 g NaCl) (1 mole Na/1 mole NaCl) ( 22.99 g Na/mole Na) = 2.989 g Na or 3.0 g Na (significant figures)
Steps:
1. Change everything to moles: use molar mass/molecular of NaCl
2. Find the molar ratio: since there are 1 Na in every NaCl, then the ratio of NaCl to Na is 1:1
3. Change moles back to grams: use the molar mass/molecular weight of Na
4. Watch out for significant figures!
I hope this is right
72.0 grams NaCl (1 mole NaCl/58.44 grams) = 1.2 moles of sodium chloride
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1 mole NaCl = 58.44g 0.1601mol NaCl x 58.44g NaCl/mol NaCl = 9.35g NaCl
1mole NaCl = 58.443g 20.0g NaCl x 1mol/58.443g = 0.342mol NaCl
NaCl has a molar mass of 22,989 769 28 + 35,453 = 58,442 769 28 g Na has an atomic weight of 22,989 769 28 g. % Na = 22,989 769 28 ÷ 58,442 769 28 = 39,337 Mass of Na in 38,1 grams of NaCl = 0,39337 x 38,1 g = 14,987 g 22,989 769 28 g of sodium contain 6,02214129.1023 atoms of sodium (Avogadro number). Atoms of sodium in 14,987 g of NaCl: (14,987 x 6,02214129.1023 )/22,989 769 28 = 3,926.1023 atoms
The answer is 1,98 g sodium.
1.946 moles NaCl (58.44 grams/1 mole NaCl) = 113.7 grams sodium chloride ======================
72.0 grams NaCl (1 mole NaCl/58.44 grams) = 1.2 moles of sodium chloride
There are 9.3504 grams of Sodium Chloride. Calculations: 0.160 mol NaCl (58.44g/mol) = 9.3504g NaCl
The percentage of sodium in NaCl is 39,666.So, 75 x 39,666/100= 29,75 g sodium in 75 g NaCl
20.67 grams NaCl (1mol NaCl/58.44 g NaCl) = 0.3537 moles of sodium chloride
Amount of NaCl = 8.0/58.5 = 0.137mol In each unit of NaCl there is one Na+ ion. Mass of Na = 0.137 x 23.0 = 3.15g
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
Atomic mass of sodium = 22.99 Atomic mass of chlorine = 35.45 Total mass = 58.44g 58.44g of NaCl contains 6.023 x 1023 atoms ... 18.035g of NaCl contains 18.035x6.023x1023/58.44 = 1.858x1023 atoms!
The answer is 2337,59 g NaCl.
Balanced equation first. 2Na + Cl2 -> 2NaCl 35 grams NaCl (1 mole NaCl/58.44 grams )( 1 mole Cl2/2 mole NaCl )( 70.9 grams Cl2/1 mole Cl2) = 21 grams of Cl2 needed
145 grams NaCl (1 mole NaCl/58.44 grams)(1 mole Na +/1 mole NaCl)(6.022 X 1023/1 mole Na +) = 1.49 X 1024 ions of sodium =====================