A: No problem but don't expect the power to increase
A relay cannot be used to power a motor. It can be used to control the motor by wiring the motor circuit in series with the relay contacts.
It is kind of transformers called center-tap transformer its main function is to transform primary voltage to 2 secondary voltages or vice versa. In your statement the transformer will convert the input voltage to 2 voltage each is 9v or the opposite it will convert the 2 input voltages with each 9v to a certain value depending on the turns ratio of the transformer.
The voltage would 9V minus any drop in the battery.
9v
9v and 4.25v, measured from a working transformer inside the clock radio.
A relay cannot be used to power a motor. It can be used to control the motor by wiring the motor circuit in series with the relay contacts.
Are you going to use the 9-volt motor as a dynamo, and the 9-volt dynamo as a motor? Yes, the motor can rotate the dynamo because DC motors and DC generators are actually the same thing--they just apply power to the terminals of a motor to make it turn, and turn the shaft of a generator to make power appear at the terminals. Having said that, if you're going to try to connect the shaft of a 9v motor to the shaft of a 9v dynamo, and use the dynamo to power the motor so as to create a perpetual motion machine...that won't work. The motor wastes a little bit of energy, as does the dynamo. It is possible to build a device that uses a motor to drive an alternator, which is the AC version of a dynamo. You power the motor from the AC grid, and power something that's very sensitive to noise on the line from the alternator. This is called a Motor Generator set, and it's how they powered Cray-1 supercomputers.
Yes, a 9v 1100mA power adapter work with your 9v 500mA device. The mA number is the maximum amount of amperage that the adapter will produce without overloading itself. At 500 mA the adapter will only be working at half load.
No.
I = p/v = 100w/9v = 11.11ai = p*v = 100w*9v = 900ai = (p/2)*v = 50w*9v = 450ai = p*2*v = 100w*(9v + 9v) = 8100a
9v batteries are used to power the pick up's up guitars.
No. Your portable radio needs 800mA to operate. Your adapter can only produce 400mA. If you make the connection the adapter will rapidly heat up and probably burn out.
this is an expression with a variable that is "v" 9v+74
You can use any 9v adapter as long as the output amperage is rated higher than the amperage rating of your appliance so yes a 600ma adapter can be used to power a 500ma or 400ma appliance
No. The windings are set for 9vdc and will not step down to 5vdc.
No. The adaptor will overheat.
3v2 + 9v = 3v (v + 3)