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It is entirely impossible to say. To give you some sort of answer i will assume that the mother is not a carrier of blue eyes (ie she has the alleles BB) then, as the father must have both blue alleles (ie he is bb). Here an upper case B representing brown eyes is uppercase because that is the dominant allele. So every child they have will have Bb and therefore will be a brown eyes carrier of the blue eye trait. However the mother might be a carrier (ie have alleles Bb). This means that, if you used a punnet square, top left would be Bb, top right would be bb, bottom left would be Bb and bottom right would be bb. So 50% of the options show the alleles for blue eyes and the other 50% show the alleles for browneyed carriers of the blue eye trait. There is would be a 50% percent chance in each of their children that they would be brown eyed and 50% chance that theyed be blue eye.

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15y ago
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13y ago

Brown eye gene = B

Blue eye gene = b

Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb.

If you have one parent who only has the gene for brown eyes, BB, and one parent who only has the gene for blue eyes, bb, then all the children will have brown eyes. Example: One parent gives a B, the other gives a b. Bb = brown eyes. Here's why: When you have two alleles (coding sequences) from genes that are at odds with each other, one version will override the the other. When dealing with eye color, B always dominates b. But these children now carry the b gene in them, and could pass it down to their own children. Some of them, depending on the other parent, could end up with blue eyes.

If one parent is Bb, and the other is bb, then each time they have a child, there is a 50% chance it will have blue eyes. Example: First parent is Bb, second parent is bb, then their children will end up as either Bb, bb, Bb, bb. If both parents carry the genes for brown eyes and blue eyes, then each time they have a child, there is a 25% chance it will have blue eyes. Example: First parent is Bb, second parent is Bb, then their children will end up as either BB, Bb, Bb, bb.

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15y ago

Yes, it is possible for a man with blue eyes and a woman with brown eyes to have a child with brown eyes as brown eyes are a dominant genetic trait

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Q: Brown eye man marries a blue eyed woman what color eyes are the offspring?
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If a brown eyed man marries a brown eyed woman can they have a green eyed child?

Yes. There are at least five genes that contribute to eye color. It is quite possible for both parents to have brown eyes (which are dominant) and yet carry other genes that can produce a green-eyed child.


How can a woman produce a baby with pretty eyes?

if the guy have brown eyes and the girl have blue eyes. what color eyes will the new born have ?


A man heterozygous for blood type A marries a woman heterozygous for blood type B The chance that their first child will have type O blood?

25% for blood type O, 50% for blodd type AB, and 25% for A.


What are the offsprings when woman who is a carrier for colorblindness marries a man who has colorblindness?

The most common type of color blindness is a sex-linked trait, meaning the gene is carried on the chromosomes that determine sex. In this case, it's carried on the X chromosome. There are other types of color blindness that are inherited that are not sex-linked, so it doesn't matter which parent is the carrier. Males are XY, and therefore can pass either an X or Y to their offspring, making them the actual determinants of the sex of the offspring. Females are XX, and so can only contribute an X. In the case of color blindness, since males only get one X, if that has the gene for color blindness on it, the male will be color blind (in this case, we'll call that one "x" rather than "X". In the case of females, she has two - so if only ONE of her X has the gene, she will be a carrier, but will not have it (Xx). If her father is colorblind (xY), and her mother is a carrier (Xx), she has a 50% chance of being colorblind (she'll either be "xx" or "Xx). If her mother IS colorblind (xx) and her father is too (xY), then there is only one outcome: "xx". So, if a color blind mother (xx) has children with a non color blind father (XY), there are the possibilities: xX, xY. Her daughters will be carriers, and her sons will be color blind. If a color blind mother (xx) has children with a color blind father (xY), then these are the possibilities: xx, xY. All children will be color blind. To sum up, a mother with sex-linked colorblindness will always have color blind sons, and daughters will have a 50% chance of being color blind, depending on if the father is or not.


How is a male offspring formed?

Answer A man and woman get together hopefully out of love, they have intercourse and during the intercourse, the man ejackulates inside the woman's vagina. In the sperm there are thousands of eggs that a man leaves inside the woman, she fertilizes them and with good luck, she gets pregnant and the couple concerned has a baby.

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