no, infinite voltage can't be given to the primary of the transformer....if the secondary is connected to the load, then over voltage will damage the load, if secondary is open circuited, then the infinite voltage can breakdown the transformer internal insulation,
Given a Transformer with 110vac at 1 amp applied to the primary with 1000 turns and the secondary of 500 turns what is the voltage current and power of the secondary?
The input voltage (primary) and output (secondary) of a transformer is determined by the manufacturer. Transformers are bought to accommodate the voltage that is needed on the primary side and to what voltage is needed on the secondary side.
To calculate the transformer ratio when the output voltage is known, you can use the formula: Transformer Ratio (Turns Ratio) = Output Voltage (Secondary Voltage) / Input Voltage (Primary Voltage). If you're given the output voltage and the input voltage, simply divide the output voltage by the input voltage to obtain the turns ratio. This ratio indicates the relationship between the number of turns in the primary coil to the number of turns in the secondary coil.
The Load will consume part of the power and therefore reduce the current (voltage ) available for the secondary part of the transformerAnswerYou cannot apply a load to the primary of a transformer which, by definition, is the winding connected to the supply voltage. Your question makes no sense.
A Step Up Transformer is one whose secondary voltage is greater than its primary voltage. This kind of transformer "steps up" the voltage applied to it.The Step Up transformer is designed to increase the voltage from the primary winding to the secondary winding.A Step-Down transformer is one whose secondary voltage is less than its primary voltage. The step down transformer is designed to reduce the voltage from the primary winding to the secondary winding. This kind of transformer "steps down" the voltage applied to it.The basic equation for stepping up or stepping down the voltageNp/Ns is known as the turns ratio.The induced voltage in the secondary winding (Vs) is in proportion to the primary voltage (Vp) and is given by the ratio of the number of turns in the secondary (Ns) to the number of turns in the primary (Np).I to answer basic transformer questions.
when dc supply is given to transformer at primary winding , the output at secondary winding will be zero.Because to induce voltage ,countnie changing flux is required ,that can not be obtained from dc supply...........
The transformer impedance is the amount of voltage applied for transformer during the load test.Answer.I really don't agree with the answer given by the previous user.Impedance is the total vector opposition offered by the transformer to the flow of current i.e the vector sum of its pure resistance (R) and it's inductive reactance (XL). http://en.wikipedia.org/wiki/Electrical_impedanceAnother AnswerThe 'impedance' of a transformer is usually expressed as a 'percentage impedance', which is defined (perhaps rather confusingly!) as the ratio of the primary voltage that will result in the full rated current flowing through the secondary, to the rated primary voltage.
The number of primary and secondary turns, or turns ratio, determine the secondary voltage given a particular primary voltage. So, for instance, if the primary voltage is 480/277 wye, and the desired secondary voltage is 208/120 wye, the turns ratio would be 2.3:1. If the primary and secondary voltages are the same, then yes, the number of turns on primary and secondary would be the same. But if you're not converting delta to wye or vice-versa, why would you have a transformer with the same input and output voltage, other than an isolation transformer?
Your question reveals a misunderstanding of how a transformer works.The primary current of a transformer is determined by the secondary current, not the other way around. When the secondary voltage is applied to a load, a secondary current flows, and its value is determined by the secondary voltage and the load impedance. This secondary current then determines the value of the primary current.
Winding copper losses of a transformer can be measured in a short circuit test of a transformer. Impedance voltage is given to the primary and the secondary is often shortcircuited. (some times the reverse is done of this). Full load currents are made to flow in both primary and secondary circuits. This current flow heats up the 2 windings of the transformer. Power consumed at this time gives the transformer copper losses.
It depends on how many amps it was designed for. A 12.5kV/600v 10kVA 3 phase transformer can handle ~.5 amps on the primary and ~10A on the secondary. A 600/120V 10kVA 3 phase transformer can handle ~10A on the primary and ~50 on the secondary.
The supply is given on the high voltage side of transformer because the supply voltage required to circulate rated current through the transformer is usually very small So energy is saved.