C code. This has been tested. Example usage in main(). # include # include typedef struct node { int data; struct node *left; struct node *right; } NODE; NODE *alloc_node() { return calloc(sizeof(NODE), 1); } NODE *makelist(int data) { NODE *root = alloc_node(); root->data = data; root->left = root; root->right = root; return root; } /* Insert data *AFTER* the positionth node. */ NODE *add(NODE *position, int data) { NODE *new = alloc_node(); new->data = data; new->left = position; new->right = position->right; (position->right)->left = new; position->right = new; return new; } void print_list(NODE *start) { NODE *this = start->right; printf("[%d, ", start->data); while ((this != NULL) && (this != start)) { printf("%d, ", this->data); this = this->right; } printf("]\n"); } void delete_list(NODE *start) { NODE *next = start; NODE *this; NODE *end = start->left->right = NULL; while (next != NULL) { this = next; if ((next = next->right) != NULL) { /* Sever links if they exist. */ next->left = NULL; } free(this); } } int main() { NODE *root = makelist(1); NODE *next = add(root, 2); next = add(next, 3); next = add(next, 4); /* 1 * 4 2 * 3 */ printf("%d\n", root->right->data); printf("%d\n", root->left->data); print_list(root); delete_list(root); return 0; }
sorry
pseudo code algorithm to create a linked list
theory part to how u can insert element at middle of link list ?
Insert newNode into a linked list after targetNode Node currentNode = root while currentNode != targetNode currentNode = currentNode.next newNode.next = currentNode.next currentNode.next = newNode
The difference is how many pointers each node has, and what they are pointing to. A linked list is comprised of "Nodes" each node contains data as well as 1 or more pointers. A singly linked list has one pointer per node, and a doubly linked list has 2 pointers per node. Some programs use several pointers per node. The purpose of these pointers is to hold the list together. In a singly linked list, you can view a node and can then move on to the next node that it is pointing to until you've passed through them all. A doubly-linked list would have a pointer to the next node as well as to the previous node. Thus you can move forward and backward through the list. A circularly-linked list doesn't necessarily have a set number of pointers because it simply means that the last node points to the first node creating a big circle. A non-circularly-linked list would not contain this last to first pointer and thus you would eventually reach the end of the list and stop.
To search for an element in a linked list, you iterate the list, looking for the element, and either return the element or an indication that it was not found. for (ptr = first; ptr != null; ptr = ptr.next) if (ptr.value == searchvalue) break; This will either leave ptr with the address of the found element, or null, if not found.
Add weights to the elements of the queue and use an algorithm to sort the queue every time an element is added.
Create a new node, making sure it is not allocated locally in the function and thus will not be destroyed when the function execution finishesFill in dataUse the "last node" pointer in the list and copy the "next" pointer location (pointing to the first node) into the new nodes "next" pointerSet the "last node" "next" pointer to point to the new nodeChange the list's "last node" pointer to point to the new nodeFor an example of implementation see: How_you_insert_a_newnode_in_singly_circular_link_list
Linear time. O(n).
write pseudocode for link list
To delete a linked list walk through the list and delete the memory allocated to each element, remembering the next element address, and then iterating or recursing the process using the next element address, until the next element address is null.
please give me an algorithm and a corresponding flow chart that displays list of numbers from 1 to 20.