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Yes you can, the top row would have Cc, which is heterozygous for the curly hair. The side column would be cc, which is homozygous recessive. The top right box would be Cc, the top left would be cc, the bottom right would be Cc, and the bottom left would be cc.

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Q: Can you make a punnett square of heterzygous for curly hair mating with a homozygous recessive for stright hair?
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Could 2 people with a widows peak have a child with a straight hairline and could 2 people with a straight hairline have a child with a widows peak EXPLAIN?

Yes to the first one, no to the second one. Firstly, widow's peak is caused by a dominant gene while a straight hairline is caused by a recessive gene. Let 'H' be dominant and 'h' be recessive. So for a dominant gene, the trait still will be expressed whether the genotype of the person is homozygous dominant(HH) or heterozygous(Hh). For a recessive gene however, the trait will only be expressed when the genotype of the person is homozygous recessive (hh). So two people with a widow's peak CAN have a child with a stright hairline, provided both of their genotypes are Hh. This is because by crossing their genotypes, they can have a possibility of having child with the genotype HH(widow's peak), Hh(widow's peak), and also hh(straight hairline). The ratio of these three possibilities however, are 1:2:1. So the odds of having a child with a straight hairline in this case is 1:3. If the two people who have widow's peak have the genotype HH or one of them HH and the other Hh, then the possibility of having a child with a straight hairline is 0. This is because by crossing their genotypes together, the genotype of the child will either be HH for the first case, and HH or Hh for the second case. For two people who have a straight hairline, the genotype of both will definitely be homozygous recessive (hh), thus child will definitely have the recessive gene. Therefore, it is not possible for two people with straight hairline to have a child with widow's peak.


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