No, Phosphorus has different oxidation states in both two ions.
In Phosphides, oxidation state is -3, while oxidation state is +5 in Phosphates
No. Oxidation number is the same as oxidation state.
Yes, the oxidation number is the same as the charge on the ion.
Atomic oxygen has oxidation number 0. Molecular oxygen also has 0 as oxidation number. It would be the same for five oxygen molecules as well.
Any individual atom has an oxidation number of 0.
the charge on a mono-atomic ion is the same as the oxidation number, for a polyatomic ion the charge is the sum of the oxidation numbers of its constituent elements.
No. Oxidation number is the same as oxidation state.
Yes, the oxidation number is the same as the charge on the ion.
Phosphate is a chemical group with the formula R3PO4 where R represents a generally reduced chemical group such as a methyl group or a Hydrogen atom for covalent Phosphate compounds and PO4(-3) for the Phosphate anion with 4 Oxygen atoms covalently bonded to a central Phosphorus atom with 3 negatively charged electrons shared between the four Oxygen atoms. Phosphide is an anion where Phosphorus has three electrons bound to it. It is an extremely strong base in contrast to Phosphate which is a significantly weaker base. Phosphide is also a very strong reducing agent.
Atomic oxygen has oxidation number 0. Molecular oxygen also has 0 as oxidation number. It would be the same for five oxygen molecules as well.
I think it is the same "Magnesium phosphide"
Any individual atom has an oxidation number of 0.
the charge on a mono-atomic ion is the same as the oxidation number, for a polyatomic ion the charge is the sum of the oxidation numbers of its constituent elements.
carbon suboxide C3O2 OCCCO. The oxygen atoms have an oxidation number of -2 same as normal, (only when O is bonded to O as in peroxides is the oxidation number not -2)
MnO2 manganese(IV) oxide. Oxygen has a -2 oxidation state (oxidation state is a better term here as oxidation number is better used for complexes- they give the same answer for this compound)
The oxidation number is the same as the charge that the atom has. If the atom usually loses an electron, then it is losing a negative charge and having more positive making it a + 1. If the atom loses two electrons, then the oxidation number would be +2. The same thing with gaining electrons, then there would be more negative charges then positive. If the atom gains one electron, then the oxidation number would be - 1. If the atom gains two electrons, then the oxidation number would be - 2. I hope that this was helpful.
The oxidation number of F, or Fluorine, is F-1. Since it is in the seventh group on the periodic table, it has seven valence electrons. It needs to get eight valence electrons to be stable, so it will gain one electron.
Because they have the same number of valence electrons