To a situation like this, you must apply an electronegativity difference test.
If ENhigh - ENlow > 0.5, the bond is ionic
If ENhigh - ENlow < 0.5, the bond is covalent
This is just a generality and different sources list different thresholds.
ENoxygen = 3.5
ENsodium = 0.9
3.5 - 0.9 = 2.6. Certainly an ionic bond.
Sodium peroxide, Na2O2, is an ionic compound. There are covalent bonds present in the peroxide ion itself.
Na2O sodium oxide is ionic.
No, it's ionic
yes
inorganic
Ionic
The chemical bond for NaOH is a covalent bond.
The sodium and hydroxide are ionically bonded: Na+ OH-
OH -Is the polyatomic ion hydroxide and is covalently bondedNa + and OH -Make up the ionically bonded compound sodium hydroxide.
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
No, NaOH is a compound
The chemical bond for NaOH is a covalent bond.
The sodium and hydroxide are ionically bonded: Na+ OH-
Na --- O | H Both are Covalent Bonds Chemical Formula: NaOH
OH -Is the polyatomic ion hydroxide and is covalently bondedNa + and OH -Make up the ionically bonded compound sodium hydroxide.
3.42 moles NaOH (39.998 grams/1 mole NaOH) = 137 grams NaOH
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
208g NaOH
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
No, NaOH is a compound
Determine the number of moles 15.5 g NaOH 15.5 g NaOH x (1 mole NaOH/39.9971 grams NaOH) = 0.388 moles NaOH Molarity = moles NaOH/L solution 0.540 M = 0.388 moles NaOH/L soln L soln = 0.718 L --> A
NaOH and HCl