Well every question that has ever been submitted that wasn't trashed because of lack of quality or inappropriate material is somewhere here on the websites. If you are looking for a specific question you can type it into the box or you can click on Browse Categories at the top and browse for all the questions!
The deletion log is a log of all questions that Advanced Supervisors have deleted from WikiAnswers.
You keep answering questions.
Every day, millions of people log in or just check this site out and answer or ask questions.
Oldest unanswered questions keep on changing.
It is a guest on WikiAnswers who did not log in
There are so many questions on WikiAnswers that it is impossible to total exactly how many questions there are. Even now, questions are being asked, so the total will always keep changing.
If you are an anonymous contributor at wikianswers, you participate in wikianswers but without a wikianswers account.
Just Keep on asking silly questions and it will get over 100 million questions
WikiAnswers will answer questions ! You have to remember - this is not a 'live' site (like a chat room) - it's a forum. People post their questions, and users browse the questions when they log-in. Different users like different questions, therefore - you need to be patient enough to wait for someone to read your question (Including this one) - before they can answer it !
to find out info from real people to questions that they need answering or if your answering questions its because they want people to know that they are helping them unlike me hope this was useful
Yes , you can answer the questions on wikianswers.
No, WikiAnswers does not have a log in API like Google or Facebook, so you can not use your WikiAnswers account to log on to other websites. Websites owned by Answers.com may allow you to log on with a WikiAnswers account, but 3rd party websites will not. If you see a third party website asking for your WikiAnswers password, do not give it to them - they are most likely trying to scam you out of your account.