david madienguela that's has it
v1 = initial velocity v2 = final velocity
v1 is design speed and v2 rotation speed
( | V1 - V2 | / ((V1 + V2)/2) ) * 100
[ ((v2 - v1) / |v1|) * 100 ]
No. Result= V1 + V2 = V2 + V1.
Let t1 and t2 be the times for the two stages. Then t1 = x/v1 and t2 = x/v2 Total distance = x + x = 2x Total time = t1 + t2 = x/v1 + x/v2 = x*(1/v1 + 1/v2) Average velocity = total distance / total time = 2x divided by x/(1/v1 + 1/v2) = 2(1/v1 + 1/v2) which is the Harmonic mean of v1 and v2.
Rip V1 is Classful routing protocol Rip V2 is Classless routing Protocol
5 * 10**-12 mol 32 * 10**-9 mol Concentration (M) * Volume (L) = mols C1*V1=C2*V2 (5*10**-12)*V1=(32*10**-9)*V2 (5*10**-12)*V1/(32*10**-9)=V2 (5*10**-3)*V1/32=V2 The volume of the 5 picomolar solution that you wish take = V1 The volume of the 32 nanomolar solution that you need to make V1 at 5pM concentration = V2 Take V2, and place into graduated cylinder and fill to V1.
The most common multi output systems are used for getting differential output. i.e., if V1 and V2 are the 2 outputs, then usually the difference, V2-V1 or V1-V2 is used.
The equations of motion that relate velocity, distance, time and acceleration for the specific case of "constant acceleration" can be written as follow, acceleration a = (v2 - v1)/t from which v2 = v1 + at The distance covered during t time d = vav x t, where vav refers to average velocity in the process from v1 to v2. For the case of constant acceleration vav = (v1 + v2)/2. Substituting in d we get d = (v1 + v2)/2 x t from which, v2 = 2d/t - v1 If we take the constant acceleration to be zero, a = 0, you can see that the second equation we wrote becomes, v2 = v1 (There is no acceleration), so our equation for the distance d becomes, d = v1 x t = v2 x t
Two vectors; V1 + V2=0 where V1= -V2, two opposite vectors.
work done (by) the system equals zero , W=P(v2 - v1)= zero , where v2 = v1