Typically resistance rises with temperature.
Typically resistance rises with temperature.
The heating element of an electric heater is a "resistor", the cord which conducts the electricity is not. The resistance of the element of an electric heater is very high. As current flows through the heating element, it becomes red hot and glows. On the other hand, the resistance of the cord is low. It does not become red hot when current flows through it.
The current flowing through the heating coil will depend on the resistance of the coil and the voltage of the power source. Using Ohm's Law (I = V/R), where I is the current, V is the voltage, and R is the resistance, you can calculate the current. The higher the voltage or lower the resistance, the higher the current.
The formula you are looking for is R = E/I. Resistance = Volts/Amps.
The energy transfers in the electric coil of a baseboard heater involve electrical energy being converted to thermal energy through the resistance of the coil. When current flows through the coil, the resistance generates heat, which warms the surrounding air in the room.
Voltage is current times resistance, 1.2 x 110 = 132 volts.
At 110 volts it is 0.8 amps. At 220 it is 0.4 amps. I=E/R. I=amps.E=volts R=resistance.
the water heater operates at high power compared to the lights and so the water heater requires a larger current. The wires supplying current to the water heater are thicker so that the wires have a low resistance. This reduces the risk of the wires overheating.
-kettle -electric heater that's all i have! :)) When a current passes through a wire, the wire heats up. This is caused by the conversion of electrical energy into heat energy. /the heat produced depends on the resistance of the wire.
It is 6 times 8 and the answer is in volts.
Watts = Current x Volts with your resistive heat application. To figure out resistance you need to know voltage and current. Since you are drawing 6 amps then Volts = 325/6. This means that there is about 54 volts supplying the heater which seems like a very strange supply voltage. Since Volts = Current x Resistance the resistance = 325/36.
4.12A. V=IR